At present Geeta is eight times her daughter’s age. Eight years from now, the ratio of the ages of Geeta and her daughter will be 10 : 3 respectively. What is Geeta’s present age ?
(1) 32 years
(2) 40 years
(3) 36 years
(4) Can’t say
(5) None of these

• (1) 32 years
  
  Let the present age of Geet=x and her daughter=y, then
  x=8y ---(i) and (x+8)/(y+8)=10/3 or 3x -10y =56 ----(ii)
  On substituting x=8y in (ii), we have 3*8y - 10y =56, 14y=56 or y=4
  Hence x=8y=8*4= 32
• 8 years agoHelpfull: Yes(8) No(0)
• Ans-(1) 32 years
  
  let the present age of her daughter is x and then the Geeta age=8*(x)=>8x
  so
  after 8 year the age will be 10 : 3
  then
  (8x + 8)/(x+8)= 10 : 3
  
  we get
  x=4
  
  so the present age of geeta is 8*4=32
• 6 years agoHelpfull: Yes(2) No(0)
• Answer: 1) 32 years
  
  solution:
  present age of geeta and her daughter = 8 : 1
  after 8 year = 10 : 3
  --------------------------
  2 : 2
  2 ratio = 8 years
  then
  1 ratio = 8/2= 4 years
  so, the present age of geeta is = 8*4= 32 years.
• 6 years agoHelpfull: Yes(0) No(0)
• 8-10x : 8-3x
  10x : 3x
  
  8-8x=8(8-3x)
  14x=56
  x=4
  
  10:3
  10 * 4=40
• 6 years agoHelpfull: Yes(0) No(2)
• Let present age of daughter is = x
  and geeta present age is = 8x
  8 years from now geeta will be 8x+8 and daughter will be x+8
  ratio = 10:3
  8x+8/x+8=10:3
  24x+24=10x+80
  after solving this eq. we will get x=4
  so the present age of geeta is 8x
  we have x= 4 so 8*4 = 32
  Ans = 32
• 5 years agoHelpfull: Yes(0) No(0)