If each of the three non-zero numbers a , b , and c is divisible by 3, then abc must be divisible by which one of the following the numbers?
(1) 8
(2) 81
(3) 27
(4) 122
(5) None of these

• Since, each one of the three numbers a, b, and c is divisible by 3, the numbers can be represented as 3p,3q and 3r, respectively, where p,q and r are integers.
  
  The product of the three numbers is 3p×3q×3r=27(pqr).
  Since p, q and r are integers, pqr is an integer and therefore abc is divisible by 27.
• 7 years agoHelpfull: Yes(16) No(0)
• 5
  suppose we have thre no 9,12,15
  which is divisible by3
  then abc=720
  check with the option
  as in question it is clearly said that must be divisible
  
• 7 years agoHelpfull: Yes(0) No(13)