Elitmus
Exam
Logical Reasoning
Cryptography
WHY
*NUT
----------------
OONP
OYPY-
OUHA--
------------
ONEPOP
-------------
solve this ?
Read Solution (Total 4)
-
- Start with second multiplication
W H Y*U=O Y P Y.
so U is 6.
now,Y can be {2,4,8}.It can't be zero.
Let us take 4(2 cant be taken you can verify moving few steps).
Taking U=6 and Y=4 .
Now the only value satisfying P is 0 from T *Y=P and W H 4 * 6
therefore to make P =0 we have to put put T=5.solving we will have
W H Y * U
W H 4* 6=O 4 0 4
therefore W and H can be found out to be 2 and 3 simply.
and O is 1 as it will only generate 4 at third place
So this will become
2 3 4
N 6 5
---------
1 1 N 0
1 4 0 4
1 6 H A
-----------
1 N E 0 1 0
From here N+4=1 will give N=7.so rest of the values will automatically come.
2 3 4
7 6 5
---------
1 1 7 0
1 4 0 4
1 6 3 8
-----------
1 7 9 0 1 0 - 8 years agoHelpfull: Yes(12) No(3)
- 234
765
------
1170
1404
1638
--------
179010
- 8 years agoHelpfull: Yes(1) No(0)
- let w=2 h=3 y=4 *t=5
234
765
-----------
1170
1404
1638
-------------
179010 - 8 years agoHelpfull: Yes(0) No(0)
- 2 3 4
* 7 6 4
------------------
1 1 7 0
1 4 3 4
1 6 3 8
--------------------
1 7 9 0 1 0
- 8 years agoHelpfull: Yes(0) No(0)
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