In 165 litres of mixtures of milk and water, water is only 28%. The milkman sold 40 litres of this mixture and then he added 30 litres of pure milk and 13 litres of pure water in the remaining mixture. What is the percentage of water in the final mixture?
1) 29.35%
2) 28. 57%
3) 24. 57%
4) 27. 75%
5) 26. 57%

• Initially, milk = 118.2 l, and water = 46.2 l.
  40 liters is withdrawn in same ratio as it was initially, i.e., 72:28.
  Remaining milk = 90 l, and water = 35 l.
  Now add 30 l of milk and 13 liter of water.
  Then milk = 120 l and water = 48 l.
  Percentage of water = 48*100/168 = 28.57 %
• 7 years agoHelpfull: Yes(11) No(0)
• ratio of water and milk remain same after sold of 40 ltr i.e 28/72
  now remaining quantity is 165-40= 125
  amount of water in 125 ltr is 125of 28%=35 ltr
  amount of milk in 125 ltr= 125-35=90
  now a/c to question 35+13/90+30=48/120
  water amount is 48 ltr in total amount 125+30+13=168
  hence the % of water is 48*100/168=28.57%
  2 is answer
• 6 years agoHelpfull: Yes(0) No(0)
• After he sells 40litre of the mixture,
  quantity of the mixture = 165- 40 = 125 litre
  quantity of water= (125*28)/100=35 litre
  After adding 30 litre of pure milk and 13 litre of pure water,
  quantity of water = 35 + 13 = 48 litre
  total quantity = 125 + 30 + 13 = 168 litre
  Required percentage =(48/168)*100=28.57%
• 5 years agoHelpfull: Yes(0) No(0)