A hemispherical bowl is made of 0.5 cm thick steel. Inner radius of the bowl is 4 cm. The volume of steel used in making the bowl is
(a) 55.83 cm3
(b) 56.83 cm3
(c) 113.67 cm3
(d) 58.83 cm3
(e) None of these

• B) 2*π(4.5^3-4^3)/3~=56.81
• 8 years agoHelpfull: Yes(7) No(1)
• inner r= 4
  outer R=4.5
  formula= 2/3*22/7(R^2-r^2)
  (2/3) * (22/7) *(4.5*4.5*4.5 - 4*4*4)
  =56.75
• 8 years agoHelpfull: Yes(4) No(3)
• 2/3 * pi * (cube(4.5)-cube(4))
  56.81
• 8 years agoHelpfull: Yes(1) No(2)
• Thickness, t = 0.5 cm; Inner radius, r = 4 cm ; Outer radius, R = r+t = 4.5 cm;
  Vol of hollow HemiSphere = 2/3*22/7*(R^3-r^3)
  = 2/3*22/7*(4.5^3-4^3)
  = 56.8304 cm3
• 7 years agoHelpfull: Yes(0) No(0)