25 ? 36 64 129 225 FIND THE MISSING TERM

• 5^2 .... 6^2 this is one set
  8^2 129 15^2 this is another set
  Here 129=11^2+8
  How I got means
  Avg of 8 and 15 is (8+15)/2 =23/2=11.5 round it to 11
  So middle term is 11^2+ first term of that set
  So ans may be 11/2=5.5 round to 5
  5^2+5=30
  
• 8 years agoHelpfull: Yes(26) No(1)
• I think the question is wrong - it should be 121 instead of 129 [5^2, (5+1)^2,(5+1+2)^2,(5+1+2+3)^2,(5+1+2+3+4)^2]
• 8 years agoHelpfull: Yes(9) No(9)
• if 129 is 121, missing term is 5^2=25
  the sequence can be written as 5^2 ___ 6^2 8^2 11^2 15^2
  difference between the consecutive numbers are in the order 0,1,2,3,4.
  so answer is 25.
• 8 years agoHelpfull: Yes(5) No(0)
• the question is wrong.its must be 121 instead of 129 and the missing term should be after 225
  solution:[5^2, (5+1)^2,(5+1+2)^2,(5+1+2+3)^2,(5+1+2+3+4)^2,(5+1+2+3+4+5)^2]
  the missing term is 400
• 8 years agoHelpfull: Yes(3) No(6)
• ans is 49. 5^2=25, 6^2=36, 5+6=11 and 11^2=121,
  similarly...7^2=47, 8^2=64 and 7+8=15...15^2=225
• 8 years agoHelpfull: Yes(3) No(4)
• Instead of 129 it should be 121
• 8 years agoHelpfull: Yes(1) No(2)
• answer is 449
  
• 8 years agoHelpfull: Yes(1) No(4)
• 49 becoz there is a same gap btween sqares of the numbers
• 8 years agoHelpfull: Yes(0) No(1)
• I Think the question is wrong...
  129 instead of 121
• 8 years agoHelpfull: Yes(0) No(0)
• I think it should be 51
  Because after every 2 square term one no. Is double +1 to its previous term
  Like
  5^2=25,25*2+1=51,6^2=36,8^2=64,64*2+1= 129,15^2=225......
• 4 years agoHelpfull: Yes(0) No(0)