Two bars of different materials and same size are subjected to the same tensile force. If the bars have unit elongation in the ratio of 2:5, then the ratio of modulus of elasticity of the two materials will be


A. 2:5
B. 5:2
C. 4:3
D. 3:4

• According to the definition of modulus of elasticity, it is tensile stress to the tensile strain
  
  given that
  
  - same size and same tensile force
  -elongation in the ratio of 2:5
  
  lets take E1 and E2 as modulus of elasticity of bar 1 and bar 2
  
  Elongation of bar 1:Elongation of bar 2 = 2:5
  
  E1=(tensile stress/tensile strain) = (p/A)/strain (elongation of bar 1)
  E1 = (p/A)/2
  
  and
  
  E2 = (p/A)/5
  
  E1/E2 =((p/A)/2)/((p/A)/5)=5:2
  
  Hence the answer is 5:2
  
  Hope I am correct...Let me know in case wrong
• 7 years agoHelpfull: Yes(1) No(0)