MBA Exam

x+y=1 and x, y >0. Find the least value of (x+1/x)^2 + (y+1/y)^2.

1) 8
2) 12.5
3) 12
4) None

Read Solution (Total 1)

when x=y=1/2
(x+1/x)^2 + (y+1/y)^2 = (2+1/2)^2 + (2+1/2)^2 = 2*25/4=25/2=12.5
11 years agoHelpfull: Yes(0) No(0)

MBA Other Question

X*Y^2*Z<0 den which one of the following is true:

1) xz<0
2) z<0
3) xyz<0
4) some other option
-1^2+2^2-3^2+4^2..........-17^2+18^2 =

1) 171
2) 342
3) 513
4) 473