in a particular state, the god of rain announces that there will be raining on exactly 20 days in each calender year. if the prbobality of raining on a particular day of year 2011, 2012 and 2013 are P, Q and R respectively then which of the following relation holds true:
a) 2Q>=P+R b) Q^2 >=P*R c) 2/Q >= 1/P + 1/Q d) all of these

• Probability of raining on a particular day is 20/365(No. of favorable days/total no of days), for a leap year its probability is 20/266.
  Now we have P=20/365, Q=20/366, R=20/365.... now verify options, only option (3) is correct
  
• 8 years agoHelpfull: Yes(51) No(4)
• Ans: d)All of these
  Explanation:
  Since during each year it rains for 20 days,
  then probability of rain for each year is as follows :
  P->YEAR 2011 -> 20/365=0.0547 ;
  Q->YEAR 2012(Leap year) -> 20/366=0.0546 ;
  R->YEAR 2013 ->20/365=0.0547
  Applying these values for each relation in the option we get,
  For a)2(.054)=.054+.054 --> 0.108=0.108;(similarly for the other relations,we get equal values )
  b)(.054)^2=.054*.054
  c)2/.054 =1/.054+1/.054
  So my friends all the relations hold true and you get the magic answer. :P
  
• 8 years agoHelpfull: Yes(5) No(27)
• option C is right.....
• 8 years agoHelpfull: Yes(2) No(1)
• probability of raining on a particular day is=1/20
  so, p=1/20,q=1/20,r=1/20.
  all the above conditions satisfies this values
• 8 years agoHelpfull: Yes(1) No(8)
• in 2011 , 2012 and 2013 only one leap year
  => 2012/4=0
  so
  probability 20 days in each calendar year
  so probability 20/2011, 20/2012, 20/2013
  now checking the relation
  a) 2Q = 22*40/2011=40/366, P+R= 40/365 (condition false or inequalities)
  b) Q^2= (20/366)^2 , P*R= 40/(365*365)(condition false or inequalities)
  c) 2/Q= (2*366)/20 , 1/P + 1/Q =(365/20) + (365/20) (condition true or inequalities)
  so option c is true
• 7 years agoHelpfull: Yes(1) No(0)
• a) is the solution
• 8 years agoHelpfull: Yes(0) No(2)
• Here 2012 is leap year means probablity Q=20/366 and for 2011 and 2013 P=R=20/365
  so by checking all options we get that all are satisfying so
  Ans = (d) all of these
• 8 years agoHelpfull: Yes(0) No(1)
• Is any1 attempt this Q in xm ,i wants to kno correct ans plz help me
  
• 8 years agoHelpfull: Yes(0) No(0)
• Option c answer... don't go in decimal.
• 8 years agoHelpfull: Yes(0) No(0)
• C would be answer
• 7 years agoHelpfull: Yes(0) No(0)
• how you will know that which one is a leap year ??
• 7 years agoHelpfull: Yes(0) No(1)