11*11=171
12*12=220
13*13=251
14*14=304
15*15=?

• Answer: 339 Calculation: Lets Say
  A= 11*11=121-171=50
  B= 12*12=144-220=76
  C= 13*13=169-251=82
  D= 14*14=196-304=108
  E= 15*15=225-(???)=. 114
  Now difference between A & B= 26 B&C=6 Again C&D=26 Hence D & E difference should be 6 again( As this is the pattern of puzzle). This 6 Should be added last previous difference no i.e 108 + 6=114 This 114 should be added to 15*15=225 Total comes to 339.
• 7 years agoHelpfull: Yes(0) No(0)
• 11*11=121[171-121=50]
  12*12=144[220-144=76]
  13*13=169[251-169=82]
  14*14=196[304-196=108]
  if we see the given series the orginal solution is added with alternate 26 and 6.
  in first 76-50=26, 82-76=6,108-82=26, and hence the solution for 15*15 should be 225+(108+6)=339
• 7 years agoHelpfull: Yes(0) No(0)
• take an ex: 23 25 27 29 31
  add 1 st and 3rd term =23+27=50/2
  =25
  so,
  given a+c=146/2=73;
  the no will be like 71,73,75,77,79
  so e value is 79
• 7 years agoHelpfull: Yes(0) No(0)