How many positive number less than 1000 have sum of there digit 17?

• digits between 1-100 sum 17 =only 2 (89,98)
  digits between 101-200 sum 17 =3 (188,179,197)
  digits between 201-300 sum 17 = 4 (296,287,278,269)
  and so on.....
  digits between 301-400 sum 17 =5
  digits between 401-500 sum 17 =6
  digits between 501-600 sum 17 =7
  digits between 601-700 sum 17 =8
  digits between 701-800 sum 17 =9
  digits between 801-900 sum 17 =10
  but in
  digits between 901-999 sum 17 =9 (980,971,962,953,944,935,926,917,908)
  so total number is
  2+3+4+5+6+7+8+9+10+9=63
  
• 7 years agoHelpfull: Yes(15) No(2)
• I think answer is 75.
  digits between 1-100 sum 17 = 2 (89,98)
  digits between 101-200 sum 17 =3 (188,179,197)
  digits between 201-300 sum 17 = 4
  and so on
  we have
  2+3+4+5+6+7+8+9+10+11=65
  
  I might be wrong. please correct me!
  
• 7 years agoHelpfull: Yes(3) No(1)
• I think answer is 65.
  digits between 1-100 sum 17 = 2 (89,98)
  digits between 101-200 sum 17 =3 (188,179,197)
  digits between 201-300 sum 17 = 4
  and so on
  we have
  2+3+4+5+6+7+8+9+10+11=65
  
  I might be wrong. please correct me!
• 7 years agoHelpfull: Yes(3) No(2)
• i think it will be 75.
  because 2 digit numbers whose sum is 17 are 89 and 98.
  in 3 digit numbers whose sum is 17 starts from (1,8,8) which can be 3 ways
  and(1,9,7) in 6 ways.
  similarly,(2,8,7),(2,9,6) --------12 numbers can be formed ,
  (3,9,5)(3,8,6)(3,7,7)-----------15 numbers can be formed,
  (4,9,4),(4,8,5),(4,7,6)---------15 numbers can be formed,
  (5,9,3),(5,8,4),(5,7,5),(5,6,6)-----18 numbers can be formed,
  (9,8,0),(9,0,8)(8,9,0)(8,0,9)------4 numbers can be formed
  
• 7 years agoHelpfull: Yes(2) No(5)
• Answer will be 65
  In my case 1 sorry I say 5 no bw 100 to. 200 ....it will be three only
  See My previous answer
• 7 years agoHelpfull: Yes(2) No(2)
• i guess 64
• 7 years agoHelpfull: Yes(1) No(1)
• I think answer is 75.
  digits between 1-100 sum 17 = 2 (89,98)
  digits between 101-200 sum 17 =3 (188,179,197)
  digits between 201-300 sum 17 = 4
  and so on
  we have
  2+3+4+5+6+7+8+9+10+11=75
  
  I might be wrong. please correct me!
• 7 years agoHelpfull: Yes(1) No(6)
• In the question it's not mentioned only 3 digit number ,so you have to consider 98 & 89 too. Now,let the three digits are a,b and c . Basically you have to find the number of values of a,b and c,such that a+b+c=17
  So there are 19c2 ways, in this we have to subtract the case in which a,b,c can be zero. So, 19c2-(9c2*3)=63
  So total numbers less than 1000 having sum of their digits as 17 is 63+2=65. This is a right answer.
• 7 years agoHelpfull: Yes(1) No(1)
• my ans is
  1330
  
• 7 years agoHelpfull: Yes(0) No(4)
• i guess its 48....bcz the smallest 2 digit num that sum 17 is 98.....so the no of combinations of their sum is 48....
• 7 years agoHelpfull: Yes(0) No(1)
• No of 2 digits=2
  No of 3 digits=fix first hundreds digit
  When it is 1,we have 5 ways
  I.e 187,188,178,197,179....
  Similarly
  For 2. 4
  For 3. 7
  For 4. 6
  For 5. 7
  For 6. 8
  For 7. 9
  For 8. 10
  For 9. 9
  
  Total = 65+2= 67
• 7 years agoHelpfull: Yes(0) No(4)
• x+y+z=17
  
  so no of possible solutions is given by
  N+R-1 C R-1
  
  N= 17 R= 3
  so ans = 171
• 7 years agoHelpfull: Yes(0) No(0)
• Ans is 171
• 7 years agoHelpfull: Yes(0) No(0)