A plane left half an hour later than the scheduled time and in order to reach its destination 1500 kilometers away in time, it had to increase its speed by 33.33 percent over its usual speed. Find its increased speed.

• 1000 km/hr
  
  Given distance=1500 km, Let usual speed=x km/hr, then increased speed=33.33% more than the usual=x*(100+33.33)/100=1.3333x= 4x/3
  As per the given condition, the distance of 1500 km is covered in 1/2 hour less time with the increased speed, so 1500/(4x/3) = (1500/x) - (1/2)
  => 4500/4x = (3000-x)/2x
  => 4500 = 6000 - 2x
  => x= 1500/2= 750
  So increased speed= 4x/3= 4*750/3=1000 km/hr
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