A tank of 425 litres capacity has been filled with water through two pipes, the
first pipe having been opened five hours longer than the second. If the first pipe
were open as long as the second, and the second pipe was open as long as the
first pipe was open, then the first pipe would deliver half the amount of water
delivered by the second pipe; if the two pipes were open simultaneously, the
tank would be filled up in 17 hours. How long was the second pipe open?

• Ans. 15
  Let the 1st and 2nd pipe be x and y respectively
  and time = z hours
  
  A/Q
  y=2x (since first pipe would deliver half the amount of water
  delivered by the second pipe)
  (x+y)*17 =425
  x+y =25
  putting the value of y then we get
  3x=25
  x=25/3 and y =50/3
  (z+5)25/3 + z(50/3) =425
  from you can find z which = 15.3 so ans is 15
  
  
• 7 years agoHelpfull: Yes(5) No(14)
• ans: 15
  
  As we know the formula w=e*t;
  
  so here work =425
  and time =17
  so efficiency e=w/t = 425/17=25;
  so 1st pipe+2nd pipe efficiency =25;
  so from the qns first pipe having been opened five hours longer than the second.
  
  which means (x-5), x;
  so (x-5)+x=25;
  2x=30;
  x=15;
  so 1st pipe =10, 2nd pipe=15;
• 7 years agoHelpfull: Yes(3) No(7)
• Check time and work LOD II question number 28 (page number :: 307) of Arun Sharma .
  
  answer is 15 hr.
• 7 years agoHelpfull: Yes(1) No(0)