A part of Rs. 38800 is lent out at 6% per 6 months. The rest of the amount is lent out at 5% per annum after 1 year. The ratio of interest after 3 years from the time when first amount was lent out is 5:4. Find the second part that was lent out at 5%.

• for 6 months , r= 6%
  for one year, r=12%
  let first part that was lent out be x;
  second part = 38800-x;
  x*12*1:(38800-x)*5*2=5:4 (as second pat was lent out after one year, so the interest would be calculated for 2 years)
  After solving we'll get,
  x=10,000
  second part= 38800-10000=28,800
• 8 years agoHelpfull: Yes(2) No(0)
• Let the 1st part that is lent out be x at 6%. then 2nd part will be (38800-x) at 5%.then the S.I1 of 1st part is (p*r*t)/100 = (x*6*6)/100 [t=6 becoz we r calculating till 3yrs & der is six 6months in 3yrs]
  similarly S.I2 of 2nd part = {(38800-x)*5*2}/100 [t=2 since the 5% rate is to be calculated after the 1st year & per annum, so no. of years left is 2]therefore, S.I1/S.I2=5/4, by calculating it we get x=10000So, 2nd part is 38800-10000=28800
• 8 years agoHelpfull: Yes(1) No(0)
• ( (x*12*3) / 100 ) / (38800-x)*5*2) =5/4
  6% for 6 month
  so 12% for 1 year
• 8 years agoHelpfull: Yes(1) No(1)