4oo students took a mock exam in Delhi, 60% of the boys and 80% of the girls cleared the cut off in the examination. If the total percentage of students qualifying is 65%, how many girls appeared in the examination?

• 60%*x+80%*(400-x)=65%*400
  Ans=100
• 8 years agoHelpfull: Yes(20) No(1)
• B + G = 400
  .6B + .8G = .65 x 400...
  Solve the two.... Ans is 100 girls appered in exam and 80 qualified
• 8 years agoHelpfull: Yes(3) No(2)
• Use allegations Basic formula
  (80-65)/(65-60)=3/1
  (14)*400 = 100
• 8 years agoHelpfull: Yes(3) No(1)
• let the no of boys be x
  so 0.6x
  now no of girls are 400-x
  so 0.8(400-x)
  now 60% of boys which is 0.6x and 80%of girls which is 0.8(400-x) has cleared the exam and 65% has cleared the exam so
  0.6x+0.8(400-x)=0.65*400
  0.6x+320-0.8x=280
  60=0.2x
  x=300
  so, 400-x=100
  ans=100
• 7 years agoHelpfull: Yes(3) No(0)
• p(a)+p(b)-p(a intersection b) so 60% of pass means 40% fail, 80% of pass means 20% fail like 65% means 35%
  
  => 40+20-35=25
  so 400 of 25% =100
  
  
  
• 8 years agoHelpfull: Yes(2) No(0)
• 200 as 2 equation is made x+y=400 and 6x+6y=2600 solve it
• 8 years agoHelpfull: Yes(1) No(2)
• 1000 girls appeared.
  g+b=400
  0.8g+0.6b=0.65*400
  solve these and u will get g=1000
• 8 years agoHelpfull: Yes(1) No(1)
• By allegation method
  
  60 80
  65
  15 5
  
  Ratio Boys and Girls is 3:1
  
  400*1/4=100 Ans
• 7 years agoHelpfull: Yes(1) No(0)
• let us take that boys +girls=400
  so we can write it as girls=400-boys
  in this 60%b+80%g=60%*400
  .6 b-.8(400-.6)=260
  . 6b-320-.8b=260
  -0.2 b=260-320
  b=60/.2=300
  so the boys are 300 so reaming are 100 they are girls
  
• 8 years agoHelpfull: Yes(0) No(0)