chakkar and ghanchakkar , two guys running in a circle, one in clockwise and other in anticlockwise direction. Chakkar completes 1 km in 4 min. , so with what speed should ghanchakkar run so that they cross each other exactly 24 times ?

• question is incomplete, unless and untill the radius of circular track is not given, we can`t solve this question....
• 7 years agoHelpfull: Yes(16) No(1)
• can any one help in out in this question
• 7 years agoHelpfull: Yes(2) No(0)
• Since chakkar and ghanchakkar move in opposite direction along the circle,so they will first meet at a sum of one round between the two.
  Relative Speed of chakkar and ghanchakkar=(sc+sg)=24
  sc=1/(4/60)=15round/hr
  therefore, sg+15=24
  sg=9 round/hr
• 7 years agoHelpfull: Yes(2) No(0)
• 6 min per min
  
• 7 years agoHelpfull: Yes(1) No(15)
• when they are running in opposite direction then no of distinct meeting points =Sum of ratio of speeds in simplest form.
  Now speed of Chakkar = 25/6 m/s. Let the ratio of speed of Chakkar and ghanchakkar be k then (25/6)/ghanchakkar=k so ghanchakkar=25/6k... So
  
  24= 25/6 + 25/6k...-->>k=25/119
  So ghanchakkar= 25/6k= (25*119)/(6*25)=119/6 m/s-->>> ans
• 7 years agoHelpfull: Yes(1) No(4)
• Ghanchakkar runs 1 and half km per minute so after 36 minutes i.e ghanchakkar runs 13 1/2 km to meet chakkar
  
• 7 years agoHelpfull: Yes(0) No(1)
• what are the options?
• 6 years agoHelpfull: Yes(0) No(0)
• for one round by chkr, ganchkr makes 24 rounds. speed of chkr is 25/6 m/s.
  Let total circumference be d therefore
  d/(25/6)=24d/(speed of ghckr)
  speed=100m/s that is 6km/min
• 6 years agoHelpfull: Yes(0) No(0)