There are two bags, one of which contains 5 red and 7 white balls and the other 3 red and 12 white balls. A ball is to be drawn from one or other of the two bags ; find the chances of drawing a red ball.

• P(Getting a red ball from the first bag): (1/2)*(5/12)
  P(Getting a red ball from the 2nd bag): (1/2)*(3/15)
  P(Drawing a red ball):
  (1/2)*(5/12)+(1/2)*(3/15)= 37/120 (Ans).
• 7 years agoHelpfull: Yes(32) No(0)
• (5/12)*(1/2)+(1/2)*(3/15)
• 7 years agoHelpfull: Yes(8) No(0)
• 1/2 was multiplied as a probability to choose one bag out of two bags
• 7 years agoHelpfull: Yes(4) No(0)
• 5/12+3/15=
  37/60
• 7 years agoHelpfull: Yes(0) No(6)
• Praval Why u have multiplied with 1/2
• 7 years agoHelpfull: Yes(0) No(0)
• 5/12 *3/15
• 7 years agoHelpfull: Yes(0) No(0)
• 37/120 will be the answer
• 6 years agoHelpfull: Yes(0) No(0)
• bag 1= 5+7 = 12 sample space of bag1 = 12C1 ; probability of red = 5C1;
  bag 2= 3+12= 15 sample space of bag2= 15C1 ; probability of red= 3C1;
  final probability= 5C1/12C1 + 3C1/15C1
  = 13/30
• 5 years agoHelpfull: Yes(0) No(3)