A can do 1/2 of a piece of work as B and C does 1/2 as mch work as A and B together.If C alone can finish the work in 40 days,then together all will finish the work in-
a)30 days
b)13+1/3days
c)15 days
d)20 days

• A= 1/2 B
  C=1/2 (A+B)
  C=3/4 B
  C Finishes in 40 days
  So, C's efficiency = 100/40 =5/2% per day
  SINCE C=3/4B
  B's efficiency = 10/3% per day
  A's efficiency = 1/2 B= 5/3 % per day
  
  Total efficiency of A,B and C = 5/3%+ 10/3%+5/2%
  = 45/6
  =15/2
  
  so days taken my all to complete = 100/(15/2)
  = 200/15
  = 40/3
  = 13 (1/3)
• 7 years agoHelpfull: Yes(0) No(1)