#include
void main()
{
int a=3,b=6,c=8;
printf("%d %d %d");
getch();
}
the output is
8 6 3
HOW?

• printf() statement is always executed from right to left (when no variable is assigned).
  So, printf("%d %d %d") will execute from right to left and will give values of c,b & a respectively (the top value of stack to the lower). So, o/p will be 8 6 3
  But, when printf("%d %d %d", a,b,c) is written, then the o/p will be 3 6 8 (as the variables are already assigned in the statement).
• 8 years agoHelpfull: Yes(7) No(0)
• I got garbage values when I run this code.
• 8 years agoHelpfull: Yes(5) No(0)
• 8 6 3 because in stack top first the value of c stored then b and then a.
• 8 years agoHelpfull: Yes(3) No(0)
• The output of this program is actually unexpected or i can say compiler dependent.
  According to C standards the output should be garbage only.
• 7 years agoHelpfull: Yes(3) No(0)
• It will show a compile error, because there is no header defined specifically but #include!
• 8 years agoHelpfull: Yes(0) No(0)
• because the printf stmt always read from right to left
  so the output is 8 6 3
• 8 years agoHelpfull: Yes(0) No(0)
• last intialization value is taken first ..
  
• 8 years agoHelpfull: Yes(0) No(0)
• Garbage Value
• 7 years agoHelpfull: Yes(0) No(0)
• No. It only gives a warning ! %d needs an 'int' argument!
• 7 years agoHelpfull: Yes(0) No(0)