how many 6 digits numbers have all their digits either all odd or all even?

• Answer is: 28125
  
  With all even digits=4*5^5 (Even digits->0,2,4,6,8)
  2 _ _ _ _ _ | 4 _ _ _ _ _ | 6 _ _ _ _ _ | 8 _ _ _ _ _ (the gaps can be filled by any of the no.s 0,2,4,6,8)
  
  with all odd digitd=5*5^5
  1 _ _ _ _ _| 3 _ _ _ _ _| 5 _ _ _ _ _| 7 _ _ _ _ _ |9 _ _ _ _ _ (The gaps can be filled with any of 1,3,5,7,9)
  
  So, total number of 6digit no. with all digits odd or all even is:
  (4*5^5)+(5*5^5)=12500+15625=28125 (Ans).
• 8 years agoHelpfull: Yes(37) No(3)
• 
  They have provided a solution which considers 0 as "even" digit.
  The number of numbers with all even digits = 4*5*5*5*5*5 = 12,500
  The numbers of numbers with all odd digits = 5*5*5*5*5*5 = 15,625
  But i really doubt if we should consider 0 as an even digit.If it was mentioned just even number without any odd digits,then it was perfectly fine to include zeros.
• 8 years agoHelpfull: Yes(3) No(0)
• total no in which all digit odd =6^6
  toatl no in which all digit even=6^5*5
  
• 8 years agoHelpfull: Yes(0) No(11)
• 9 could be the answer
• 8 years agoHelpfull: Yes(0) No(1)
• _ _ _ _ _ _
  No. of odd digits = 5
  then 5^6=15625
  No. of even digits = 5
  but 0 cannot be on 1st place from left therefore there are 4*(5^5) =12500
  Total number of ways are 15625+12500=28125
• 8 years agoHelpfull: Yes(0) No(1)
• 1080 is ans...
• 8 years agoHelpfull: Yes(0) No(1)
• for even digits 4*5^5 ways because first place of 6 digit from your left hand can can be fill in 4 ways
  (except 0) and all places can be filled in 5 ways
  
  and for even places 5^6 ways
• 4 years agoHelpfull: Yes(0) No(0)