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a number divided by 84 leaves remainder 57 what is the remainder when same number divided by 12
Read Solution (Total 12)
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- ans 9
trick
add 84+57=141
now 141divided by 12 so we get 9 as reaminder - 8 years agoHelpfull: Yes(27) No(2)
- let no be x
on dividing by 84 it gives remainder 57
since every no divisible by 84 must be divisible by 12
thus number x on dividing by 12 will be like 12*y + 57 i.e. 12*y+ 12* 4 + 9
therefore we got 9 as remainder on dividing by 12 - 8 years agoHelpfull: Yes(7) No(0)
- let x be the number
x=84Q+57
(84Q+57)%12=R
let us assume Q=1
(84+57)%12=R
(141)%12=R
Remainder=9 - 8 years agoHelpfull: Yes(4) No(1)
- Answer 9
N=84x+57(question according)
So written
N=84x+57/12
So can 84 is divisible 12
57/12
So remainder 9 - 8 years agoHelpfull: Yes(3) No(0)
- Ans 9
TRICK
when we divide 57 we got a remainder of 9 - 8 years agoHelpfull: Yes(1) No(0)
- Answer 9
N=84x+57(question according)
So written
N=84x+57/12
So can 84 is divisible 12
57/12
So remainder 9 - 8 years agoHelpfull: Yes(1) No(1)
- 84*k+57=x
12*4*k+48+9=x
12(4*k+4)+9=x
hence ans is 9 - 7 years agoHelpfull: Yes(1) No(0)
- num/84= num/(12x7)
thus we r only required to check the remainder when 57 is divided by 12 which comes out to be 9 - 8 years agoHelpfull: Yes(0) No(0)
- divide 57 by 12 u will get 9 as remainder
- 8 years agoHelpfull: Yes(0) No(0)
- since 84 is multiple 0f 12 (12x8)
so,remainder 54 is divided by 12 leaves remainder 9. - 8 years agoHelpfull: Yes(0) No(1)
- 84q+57=n
12q*7+2*12+33
reminder=33
- 8 years agoHelpfull: Yes(0) No(4)
- 2,3,5,7....
2is the only even NUM in prime number so we get only one 0 i.e..2*5=10 - 6 years agoHelpfull: Yes(0) No(0)
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