Accenture
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Numerical Ability
Log and Antilog
log base 12 144p=3 then p= ?
Read Solution (Total 8)
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- 12^3=144p
p=12 - 8 years agoHelpfull: Yes(5) No(0)
- log 144p/log12=3
log 144p/log12 = log12.12.p/log12 = (log12+log12+logp)/log12 = 1+1+(logp/log12) = 2+(logp/log12)
2+logp/log12=3
logp/log12=1
logp = log12
p=12
- 8 years agoHelpfull: Yes(3) No(2)
- log base 12 144 + log base 12 p=3
2+log base 12 p=3
log base12 p =1
P=12
- 8 years agoHelpfull: Yes(3) No(0)
- log base12 12^2p=3
2p log base12 12=3
p=3/2 - 8 years agoHelpfull: Yes(2) No(2)
- log base 12 144p=3
144p=12^3
144p=12^2 *12
144p=144*12
p=12 - 8 years agoHelpfull: Yes(0) No(0)
- log144p/log12=3;
log144/log12+logp/log12=3;
so p=12 - 8 years agoHelpfull: Yes(0) No(0)
- answer is :- 12
solution is:-
=>12^3=144p
=>1728/144=p
=>p=12 - 7 years agoHelpfull: Yes(0) No(0)
- this is cryptarithmetic?
- 6 years agoHelpfull: Yes(0) No(0)
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