TCS
Company
Numerical Ability
Number System
what is the remainder when (100!)^100 is divided by 23?
Read Solution (Total 2)
-
- 100! when expanded has 23 in it ,which means the whole of (100!)^100 can be considered as a multiple of 23.so when the number is divided by 23 the remainder is 0.
- 7 years agoHelpfull: Yes(42) No(7)
- 23 is present im100! why for waiting remainder is zero
- 7 years agoHelpfull: Yes(0) No(0)
TCS Other Question