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Arithmetic
consider the sequence 1 -2 3 -4 5 -6,... what is the average of the first 200 terms of the sequence?
Read Solution (Total 15)
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- Sum of first 10 terms in that series =1-2+3-4+5-6+7-8+9-10=-5
Sum of 200 terms=20*-5=-100
Avg=-100/200=-0.5 - 8 years agoHelpfull: Yes(19) No(1)
- 1-2=-1 so the sum in the first two terms =-1
so for 200 elements it will be -100
and so the average of first 200 is= -100/200= -0.5
- 8 years agoHelpfull: Yes(7) No(0)
- answer is -100
- 8 years agoHelpfull: Yes(4) No(1)
- answer is -0.5
- 8 years agoHelpfull: Yes(2) No(4)
- average of first n odd numbers will be n.
average of first n even numbers will be n+1
in 200 numers , 100 are odd and 100 are even.
for 100 odd numbers, average is 100
for 100 even numbers average is 101.
therefore , (100-101)/2= -0.5
- 8 years agoHelpfull: Yes(2) No(0)
- -100 is the answer
- 8 years agoHelpfull: Yes(1) No(6)
- we can do this question by using arithmetic series
(1+3+5+.....+199) - (2+4+6+.....+200)
= [ {n1/2}*{(a1+l1)} ] - [ {(n2/2)}*{(a2+l2)}]
= [ {100/2}*{(1+199)} ] - [ {(100/2)}*{(2+200)}]
= -100 - 8 years agoHelpfull: Yes(1) No(2)
- @jakki... plzz explain how...??
- 8 years agoHelpfull: Yes(0) No(0)
- Number at even position = -2(n) => -2*1 , __ , -2*2 , __ , and so on
Number at odd position = odd numbers - 8 years agoHelpfull: Yes(0) No(1)
- answer is -0.5
- 8 years agoHelpfull: Yes(0) No(0)
- break down it like
1,3,5,.. + ( -2 )( 1 , 2, 3,...)
an = a1 + (n-1)d
you will get
199 - 200
= -1 - 8 years agoHelpfull: Yes(0) No(1)
- (1+3+5+..199)-(2+4+6+8....+200)
t1-t2
t1=1+3+5+...199
t2=2+4+6+.....200
t1=100/2*100(1+199)=100
t2=100/2*100(2+200)=101
now;
100-101=-1 - 8 years agoHelpfull: Yes(0) No(2)
- so much of confusion in this problem
please give one unique solution - 8 years agoHelpfull: Yes(0) No(0)
- 1,-2,3,-4,5.-6.
1-2=-1
3-4=-1
5-6=-1
there are 200 terms so we get 100 1's
avg for 100 terms =100*(-1)/200=-100/200=-0.5
- 8 years agoHelpfull: Yes(0) No(0)
- 1,-2,3,-4,5,-6........200.
sum=(1+3+5+7...199)-(2+4+6+8+....200)
=10,000-10,100
= -100. avg= -100/200
= -0.5 - 8 years agoHelpfull: Yes(0) No(0)
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