int c,a=2;
c=++a + ++a;
printf("%d",c);

• a=2;
  Now, 1st pre increment gives ++a=> a=a+1=2+1=3; 2nd pre increment gives ++a=> a=a+1=3+1=4
  So, we'll get the final value of a=4
  Now, c= ++a + ++a means, c=4+4
  So, c=8 (Ans).
• 8 years agoHelpfull: Yes(21) No(10)
• 7 because a=2 it perform preincriment operation So a=3 and again pre incriment so a=4 the add so Answer is 7
• 8 years agoHelpfull: Yes(6) No(7)
• a=2, then for 1st ++a = 3 tthen for second ++a=4
  c=3+4=7
• 8 years agoHelpfull: Yes(5) No(2)
• 8 is the o/p
  
• 8 years agoHelpfull: Yes(4) No(2)
• 8 is the required answer
  ++a pre increment operator will have higher preference than = operator.
  So a will get incremented twice and stored in the memory location as 4
  so now the value will be picked up from the memory location and c will be calculated as 4 + 4 =8
• 8 years agoHelpfull: Yes(4) No(2)
• 4 Will Be The Answer Since Preincrement Is Included
• 8 years agoHelpfull: Yes(3) No(9)
• ++a=3 so it's referred to + operator 3
  and again now the value of a is 3
  it's again incremented by 1 so the value of lateral ++a is 4 it refers the 4 to the + operator so
  3 + 4= 7
  7 is the correct answer
• 8 years agoHelpfull: Yes(2) No(0)
• assian the a value is 2
  thea above experssion pre increment
  c=4+3=7
• 8 years agoHelpfull: Yes(1) No(0)
• a=2;
  ++a=3
  ++a=4
  ++a+++a=8
  
  if a=3;
  then
  ++a=4
  ++a=5
  ++a+++a=10
• 6 years agoHelpfull: Yes(1) No(1)
• 3 will be its answer.
• 8 years agoHelpfull: Yes(0) No(5)
• 8 first all the pre increments are done hence a becomes 4
  now c=4+4=8
• 8 years agoHelpfull: Yes(0) No(1)
• @baishali roy
  Could you explain the same with one more increment.i .e
  c=++a + ++a + ++a;
• 8 years agoHelpfull: Yes(0) No(1)
• a=2
  ++a=3
  then c=3+3=6
• 8 years agoHelpfull: Yes(0) No(2)
• answer may be 7 and may be 8. its depend on compiler that how the preincremented value is going to store. so explanation of baishali roy and harsh gupra, both are right.
• 8 years agoHelpfull: Yes(0) No(0)
• Final output will be 8 as in this program "volatile" keyword is not used so there will be compiler optimization. If we use volatile int then the output would be 7. try this
• 7 years agoHelpfull: Yes(0) No(0)
• The final answer is 8.
• 7 years agoHelpfull: Yes(0) No(0)
• @balaram achuri-
  the increment operator ++a is 3 times so the final value of a is 5 which is then added as 5+5+5=15 and then assigned to c
• 7 years agoHelpfull: Yes(0) No(0)
• In a first ++a I.e(3) will assign and after that ++2 I.e(4) will assign and in expression all will sum so answer like
  C=3+4, c=7
• 7 years agoHelpfull: Yes(0) No(1)
• 7 is ans
  
  It is pre increment so it is incremented to 3 and then again incremented to 4....so 3+4 is 7
• 7 years agoHelpfull: Yes(0) No(0)
• 6
  ++a=3;a++=3
  c=6
• 7 years agoHelpfull: Yes(0) No(0)
• given a=++a means a=a+1 it is pre increment so we can add first then a=2+1=3
  now a=2 . again ++a then a=a+1 it is also a pre increment so a=a+1 a=3+1=4
  coming to the question c= ++a + ++a c=4+4 =8
  finally c=8
• 5 years agoHelpfull: Yes(0) No(0)