Some amount is lent at 6% per annum simple interest.After 1 year rupees 6800 is repaid and the rest of the amount is repaid at 5% per annum.If the second year's interest is 11/20 of the first years interest,find what amount of money was lent out.
a)17000
b)16800
c)16500
d)17500

• a)17000
  
  Let the amount=x
  Interest after 1st year= x*6/100=3x/50
  Lent sum remained after repaying 6800 Rs= x+(3x/50) - 6800= (53x/50)- 6800
  Interest after 2nd year=[(53x/50)- 6800]*5/100
  Given, second year's interest is 11/20 of the first years interest,so [(53x/50)- 6800]*5/100=(11/20)*3x/50
  => (53x/50)- 6800 = 33x/50
  => 20x= 340000
  => x= 17000
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