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HERE=COMES-SHE,(Assume s=8) Find the value of R+H+O.
Read Solution (Total 28)
-
- HERE + SHE = COMES
S=8
C must be 1 and hence H must be 9 as we are adding a four digit number and a three digit number.
C=1 & H=9
now, E + E = S = 8
so, E = 4 or 9 but H = 9 so E = 4
as it E is 4 it won't generate a carry.
now, R + H = 10 + E as E - 7 years agoHelpfull: Yes(30) No(32)
- 9494=10348-894
R+H+o=14 - 7 years agoHelpfull: Yes(27) No(10)
- 14
E+E =8
then,E=4
s=8, e+s=M 4+8=12 M=2
H+1=10 so, O=0 C=1,
now r+h=e=4 h=9
so R has to be 5 as 5+9=14 which leaves us wid a carry 1..
so M=3
so finally
R+H+O=5+9+0=14 - 7 years agoHelpfull: Yes(13) No(1)
- Give S = 8. Here E + E = S = 8(E can be either 4 or 9 )
Whatever be the value of E(either 4 or 9), E + S will generate carry
the value of H should be taken such that it should generate carry(so that H != O),because no two numbers can have same value.So taking H to be 9 as ( E + S) will generate carry.
H= 9 and E= 4
1 1----------------------------->CARRY
H E R E 9 4 5 4
+S H E + 8 9 4
------------------- -------------------------
C O M E S 1 0 3 4 8
-------------------- --------------------------
C = 1
R+H= E=4
R+9=4.
Taking R= 5 we get 14 ,E= 4 and 1 carry
M= 3
So, R+H+O = 5+9+O = 14 - 7 years agoHelpfull: Yes(9) No(4)
- 10348
- 894
-------------
9454
--------------
c=1
o=0
m=3
e=4
s=8
h=9
r=5 - 7 years agoHelpfull: Yes(7) No(0)
- here=9454
R+h+o=9+5+0=14 - 7 years agoHelpfull: Yes(4) No(0)
- HERE+SHE=COMES
9454+894=10348
R+H+O=14 - 7 years agoHelpfull: Yes(4) No(0)
- 9454+894=10348
R+H+O=14; - 7 years agoHelpfull: Yes(2) No(1)
- H=9
E=4
R=5
S=8
C=1
0=0
M=2 - 6 years agoHelpfull: Yes(2) No(0)
- H E R E = 9 4 5 4
+. S H E = 8 9 4
C O M E S = 103 4 8
R+H+O=5+9+0=14 - 5 years agoHelpfull: Yes(2) No(0)
- HERE=9454
COMES=10348
SHE=894
R+H+O=5+9+0=14 - 6 years agoHelpfull: Yes(1) No(1)
- Say h=1,e=4,r=3,e=4 then here = 1434
Say c=0,O=2,m=2,e=4,S=8(given) i.e
Comes=02248,
She=814
Here=comes-she
1434=02248-814=1434
i.e r=3,h=1,O=2 r+h+O=3+1+2=6 - 6 years agoHelpfull: Yes(1) No(4)
- HERE=COMES-SHE
COMES=HERE+SHE
HERE
SHE
+
COMES
E+E=S 4+4=8 E=4
.
.
.
.
R+H+O=14 - 5 years agoHelpfull: Yes(1) No(0)
- Sol:
HERE = COMES – SHE
HERE
+ SHE
------------
COMES
------------
E + E = S = 8 => E = 4
3 digit no. + 4 digit no. = 5 digit no.
⇒
C = 1 ,O = 0, H = 9 etc
So 9454 + 894 = 10348
10348
– 894
--------
9454
-------
R + H + O = 5 + 9 + 0 = 14 - 5 years agoHelpfull: Yes(1) No(0)
- C=0
O=6
M=3
E=4
R=9
H=5
06348-854=5494
9+5+6=20 ans. - 5 years agoHelpfull: Yes(1) No(0)
- C=1
O=0
M=2
E=4
S=8
H=9
E=4
then, 10248-894=9454
R+H+O=14. - 5 years agoHelpfull: Yes(1) No(0)
- HERO =COMES-SHE
then we can write
HERO 9ERO C=1
+ SHE +SHE H=9
----------- ----------------- S= 8 (GIVEN)
COMES 1OME8
--------- ------------
value of s=8(given) so possible number of combination of O +E=8 (1,7) (2,6) (3,5) (5,3) (6,2) (7,1)
if we take O=2 and E=6 (6+2)=8
so
9672 HERO
+ 896 + SHE
---------------- ----------
10568 COMES
------------ ------------
COMES-SHE=HERO 10568-896=9672
R+H+O=7+9+0=16
- 7 years agoHelpfull: Yes(0) No(16)
- 38 because from last value of s is 8 and we similarly calculate the other
- 7 years agoHelpfull: Yes(0) No(2)
- If s=8 then R=9,O=12,H=19 here R+O+H=30
- 7 years agoHelpfull: Yes(0) No(0)
- 14
r+h+o=14 - 6 years agoHelpfull: Yes(0) No(2)
- R+H+O=5+9+0=14
H(9) E(4) R(5) E(4)
(+) S(8) H(9) E(4)
____________________________
C(1) O(0) M(3) E(4) S(8) - 6 years agoHelpfull: Yes(0) No(0)
- We can say,
COMES+SHE=HERE;
COMES
SHE
----------
HERE
Therefore put 8 in places of S
and therefore we can say C is 1
and H is 9 so carry 1 can generate O as 0
M is 3 E is 4 S 8
Therefore R = 5 as 9+5=14
as E is 4 because 2E=8, E=4
therefore we can say
R+H+O = 5 + 9 + 0 = 14. - 6 years agoHelpfull: Yes(0) No(0)
- s=8 then E = 4 ,then E+S= 12 ,so m=2,,
R+H = 1 +3, O becomes 0 so the answer is 4 - 6 years agoHelpfull: Yes(0) No(0)
- s=8,h=9,e=4,r=5,c=1,o=0,m=2.
r+h+o= 14 - 6 years agoHelpfull: Yes(0) No(0)
- 9434 = 10248 - 814
- 6 years agoHelpfull: Yes(0) No(0)
- R+H+O=5+9+0=14
- 5 years agoHelpfull: Yes(0) No(0)
- HERE + SHE = COMES
S=8
C must be 1 and hence H must be 9 as we are adding a four digit number and a three digit number.
C=1 & H=9
now, E + E = S = 8
so, E = 4 or 9 but H = 9 so E = 4
now, R + H = 10 + E as E - 5 years agoHelpfull: Yes(0) No(0)
- 111
----------
HERE
+ SHE
----------
COMES
This problem can be said to be of AI -> Constraint satisfaction problem,
S = 8 (Given)
C = 1 (Because it is last carry forwarded digit)
H = 9 (Because it is added with nothing and though resulting a carry for 5th digit C)
O = 0 (Because it gives a carry forward)
Now E + E = S means 4+4 = 8
Therefore E = 4
Compare last second digits of all there words,
R + H = E
Resulting into R = 5 (Because H = 9 & E = 4 gives R = 5 and a carry)
Thus, R + H + O = 5 + 9 + 0 = 14 (Required Answer) - 4 years agoHelpfull: Yes(0) No(0)
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