.In triangle PQR, PQ=6 cm,PR=8 cm and QR=12 cm. Calculate the area of the triangle PQR.
A. 23.33 cm2 B. 17.5 cm2 C. 21.33 cm2 D. 28.67 cm2

• we know s=(a+b+c+)/2
  here a=6cm, b=8cm , c=12cm
  therefore s=(6+8+12)/2
  =26/2
  =13
  area of tringle=sqrt [ s (s-a) (s-b) (s-c)
  =sqrt [ 13* (13-6) *(13-8)* (13-12)
  =sqrt [ 13*7*5*1]
  =sqrt [455]
  =21.33(ans) [Here sqrt stands for square root]
• 7 years agoHelpfull: Yes(41) No(1)
• S=(6+8+12)/2
  =13
  Area=sqrt (s(s-a)*(s-b)*(s-c))
  13(13-6)(13-8)(13-12)
  =21.33cm2
• 7 years agoHelpfull: Yes(1) No(0)
• herons formula so if you calculate its 21.33
• 7 years agoHelpfull: Yes(0) No(1)
• s=(pq+pr+qr)/2;
  area=sqrt of s(s-a)(s-b)(s-c);
• 7 years agoHelpfull: Yes(0) No(0)
• answer c
  because
  s=a+b+c/2;
  s=13
  hero formula se
  
• 7 years agoHelpfull: Yes(0) No(0)
• perimeter=(12+8+6)/2=13
  Area=sqrt(13*(13-12)*(13-8)*(13-6))=sqrt(13*7*5*1)=21.33
• 7 years agoHelpfull: Yes(0) No(0)
• S=(a+b+c)/2
  Area=(s(s-a)(s-b)(s-c))^1/2
  S=13
  A=sqrt of 455=21.33cm^2
• 7 years agoHelpfull: Yes(0) No(0)
• s=6+8+12/2=26/2=13
  area=sqrt(s(s-a)(s-b)(s-c)
  sqrt(13(13-6)*(13-8)*(13-12))
  sqrt(455)=21.33
• 7 years agoHelpfull: Yes(0) No(0)
• c 21.33cm,first find semi perimeter and than place it in formula
• 4 years agoHelpfull: Yes(0) No(0)