There are 2 different blue toys, 3 different green toys and 4 different red toys. In how many ways one can choose 3 toys, such that there is at least one green toy in the chosen three?

(a) 33 ways (b) 36 ways
(c) 38 ways (d) 40 ways

• 64 ways
  
  We may have(1 green and 2 non-green) or (2 green and 1 non-green) or (3 green).
  Required number of ways = (3C1 x 6C2) + (3C2 x 6C1) + (3C3)= 45+18+1= 64
• 7 years agoHelpfull: Yes(63) No(15)
• total ways = 9C3. Number of ways not to choose green ball = 3C0*2C2*4C1 + 3C0*2C1*4C2 + 3C0*2C0*4C3. So solution will be 84 - 20 = 64 (ans)
• 7 years agoHelpfull: Yes(7) No(2)
• 64 is the ans.
  At least one green toy in the three
  so possibilities are
  (3c1*6c2)+(3c2*6c1)+(3c3*6c0)=64
• 7 years agoHelpfull: Yes(5) No(2)
• total ways=43
  total possibility(2c1*3c1*4c1+2c1*3c2+3c2*4c1+3c3)
  =43
• 7 years agoHelpfull: Yes(3) No(3)
• (3p1 x 6p2) + (3p2 x 6p1) + (3p3*6p0) as toys are different so P
• 7 years agoHelpfull: Yes(2) No(19)
• 9+5*2+7*2+1*3=36
• 7 years agoHelpfull: Yes(2) No(17)
• 33 And
  3c1*4c2+3c2*4c1+3c3*4c0
  Solve
• 7 years agoHelpfull: Yes(1) No(1)
• We may have(1 green and 2 non-green) or (2 green and 1 non-green) or (3 green).
  Required number of ways = (3C1 x 6C2) + (3C2 x 6C1) + (3C3)= 45+18+1= 64
• 7 years agoHelpfull: Yes(1) No(0)
• Total no of different toys n(s)= 9c3
  N (e)= 3c3
  possible outcome = n (e)/n (s)
  = 9c3/3c3
  = 36/1
  = 36 Ans
• 7 years agoHelpfull: Yes(1) No(4)
• selecting all toys-none of them is green toy (for atleast condition)
  selecting all toys i.e,9C3
  none og them is green i.e,6c3
  9c3-6c3=64
• 7 years agoHelpfull: Yes(1) No(1)
• answer is 33 coz there will b 3 cases : 1) 1 blue 1 green red =2c1*4c1*3c1=24
  2) 2 blue 1green = 2c1*3c2*4c0=6
  3) 2green 1blue=3c1*2c2*4c0=3 so total 24+3+6=33
• 5 years agoHelpfull: Yes(1) No(1)
• Parag kumavat pls expalin how it is done..
• 7 years agoHelpfull: Yes(0) No(0)
• 8c2+7c1+1 ways
• 7 years agoHelpfull: Yes(0) No(0)
• how can be 36 ways.............plz explain
• 7 years agoHelpfull: Yes(0) No(0)
• Tell me answer explain
• 7 years agoHelpfull: Yes(0) No(0)
• 3C1*4C2+3C1*4C1*2C1+3C1+2C2=45
  
• 7 years agoHelpfull: Yes(0) No(0)
• yaar 64 to options me b nahi hai.. plzz explain it
• 7 years agoHelpfull: Yes(0) No(0)