what is the ratio a:b if
a=b-8
a^2=b^2

options are like elitimus problem sloving

• (b-8)^2=b^2
  b^2+64-16b=b^2
  b=4
  a=-4
  a:b=1:-1
• 8 years agoHelpfull: Yes(14) No(13)
• D) can not be answered by both statement together
  1) a=b-8 a:b have many possiblities...... not sufficient
  
  2) a^2=b^2
  a=(b^2)^1/2
  a=+b or a=-b so this statement is also not sufficient
  
  1+2) here also there will be 2 possibility.... so can not be answered by both statement together
• 8 years agoHelpfull: Yes(10) No(3)
• c. Both statements are required to get the desired answer
  
  For Instance we have asked for the ratio of a:b
  
  1st condition
  
  a=b-8 or we can write it as b=a+8.... that is 8 greater than a itself.... in this point we are unable to get
  ratio as we can just guess the two numbers not prove it
  
  now the 2nd condition is a^2=b^2
  
  In these condition we have to go for hit n trial method and think of a integer which satisfy the condition
  by taking a=-4 and b=+4 the difference of which comes out to be 8 satisfes the 1st condition apt the 2nd condition too....
  
  hence, both the statements are required
• 8 years agoHelpfull: Yes(3) No(1)
• for all those people who are solving the question to give the ratio u dnt need to solve the question here its a data sufficiency problem which can be only solved if both statements are taken together
• 8 years agoHelpfull: Yes(1) No(0)
• option A is right
  because only a^2=b^2 is satisfied the statement
  
• 8 years agoHelpfull: Yes(0) No(6)
• Let us take
  a= (-4), b = 4
  These values satisfies the above equation... Thus ratio will be 1:1,as ratio is never negative.
  
• 8 years agoHelpfull: Yes(0) No(3)
• when solve both equ. we get a=-4 and b=4 so ratio is -1:1.
• 8 years agoHelpfull: Yes(0) No(1)
• a=b-8=> b-a=8
  b^2-a^2=0=>(b-a)(b+a)=0
  b+a=0
  b=4,a=-4
  Ratio=1:1
• 8 years agoHelpfull: Yes(0) No(1)
• since a^2-b^2=0
  (a+b)(a-b)=0
  but it is given that a=b-8
  so if (a+b)(a-b)=0
  then either (a+b)=0 or (a-b)=0
  so (a+b)=0
  a= -b
  a:b = -1:1
• 7 years agoHelpfull: Yes(0) No(0)
• Frnds what ever you take the value of y x is always greater than y.
  2x-2y=1
  that does mean 2x>2y
  => x>y
  => x/y>1....so only statement 1 is sufficient to ans the question.
• 7 years agoHelpfull: Yes(0) No(2)