Consider the following two curves in the X-Y plane y=(x3+x2+5) y=(x2+x+5) Which of the following statements is true for -2<= x <=2?

• The correct question is
  Consider the following two curves in the x-y plane:
  y = x^3 + x^2 + 5
  y = x^2 + x + 5
  Which of the following statements is true for -2 < x < 2?
  
  a) The two curves intersect once
  b) The two curves intersect twice
  c) The two curves do not intersect
  d) The two curves intersect thrice
  e) None of the above
  
  here x^3 + x^2 + 5 = x^2 + x + 5
  => x^3 - x = 0
  Factor: x(x^2 - 1) = 0
  Factor: x(x+1)(x-1) = 0
  x= -1, 0, 1
  Three points of intersection (D)
  
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• @Natarajan plz send all questions asked in capgemini
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• two curves intersect thrice since x^3=x ,x=0,1,-1
  
• 7 years agoHelpfull: Yes(2) No(1)
• given planes intersect each other 3 times at -1,0,1.
• 7 years agoHelpfull: Yes(1) No(2)
• where are the options?
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• I can't understand the ans so plz give a clear discription
  
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• Mr.Natarajan sir please send all questions that are asked in capgemini to my mail sir... i have exam on 13th .My mail id is raspberry.swapna@gmail.com
  
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• the two curves intersect thrice b/w -2
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• Sir, please send me all Questions to Surajdhokre94@gmail.com
• 6 years agoHelpfull: Yes(0) No(0)