Capgemini
Company
Numerical Ability
Geometry
Consider the following two curves in the X-Y plane y=(x3+x2+5) y=(x2+x+5) Which of the following statements is true for -2<= x <=2?
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- The correct question is
Consider the following two curves in the x-y plane:
y = x^3 + x^2 + 5
y = x^2 + x + 5
Which of the following statements is true for -2 < x < 2?
a) The two curves intersect once
b) The two curves intersect twice
c) The two curves do not intersect
d) The two curves intersect thrice
e) None of the above
here x^3 + x^2 + 5 = x^2 + x + 5
=> x^3 - x = 0
Factor: x(x^2 - 1) = 0
Factor: x(x+1)(x-1) = 0
x= -1, 0, 1
Three points of intersection (D)
- 8 years agoHelpfull: Yes(30) No(0)
- @Natarajan plz send all questions asked in capgemini
- 8 years agoHelpfull: Yes(18) No(16)
- two curves intersect thrice since x^3=x ,x=0,1,-1
- 8 years agoHelpfull: Yes(2) No(1)
- given planes intersect each other 3 times at -1,0,1.
- 8 years agoHelpfull: Yes(1) No(2)
- where are the options?
- 8 years agoHelpfull: Yes(1) No(3)
- I can't understand the ans so plz give a clear discription
- 8 years agoHelpfull: Yes(0) No(0)
- Mr.Natarajan sir please send all questions that are asked in capgemini to my mail sir... i have exam on 13th .My mail id is raspberry.swapna@gmail.com
- 8 years agoHelpfull: Yes(0) No(0)
- the two curves intersect thrice b/w -2
- 8 years agoHelpfull: Yes(0) No(0)
- Sir, please send me all Questions to Surajdhokre94@gmail.com
- 7 years agoHelpfull: Yes(0) No(0)
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