Let Q be any number less than 200 which leaves remainder 2 when divisible by 5 or 7. What is the sum of all those numbers of Q?

• least number which gives remainder of 2 when divided by 5 or 7 is the LCM of 5 and 7 plus 2 i.e 35+2=37.
  now,second number will 72 and by this way,we can say that sum all number less than 200 is
  
  37+72+107+142+177=535
• 7 years agoHelpfull: Yes(26) No(2)
• divisible by 5:2,7,12......197.sum of divisible 5 is 3980.
  divisible by 7:2,9,16.....198.sum of divisible 7 is 2900.
  divisible by 5,7:2,37,72,107,142,177. and sum is 537.
  so answer is 3980+2900-537=6347..
• 7 years agoHelpfull: Yes(6) No(7)
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• 7 years agoHelpfull: Yes(5) No(10)
• Numbers that leave the remainder 2 when divided by 5 are 7,12,17,22,27,32........,197 in AP where a=7,d=5
  By calculating using the formula of nth term, we get n= 39
  By using sum of n terms, s=n/2(2a+(n-1)d),s=3978
  
  Numbers that leave the remainder when 2 divided by 7 are 9,16,23,30,........,198 in AP where a=9,d=7
  By calculating using the formula of nth term, we get n= 28
  By using sum of n terms, s=n/2(2a+(n-1)d),s=2898
  
  Total sum=3978+2898=6876
  
  
• 7 years agoHelpfull: Yes(3) No(2)
• Suraj kumar dubey the question says when divisible by 5 or 7 i.e there is an or between 5 and 7. Your solution would have been correct if there was an and between 5 and 7. I hope every one understands the difference
• 7 years agoHelpfull: Yes(1) No(0)
• least number which gives remainder of 2 when divided by 5 or 7 is the LCM of 5 and 7 plus 2 i.e 35+2=37.
  now,second number will 72 and by this way,we can say that sum all number less than 200 is
  2+37+72+107+142+177=537
• 7 years agoHelpfull: Yes(0) No(0)