if cost price of 13 articlels is equal to selling price of 20 pens.find gain or loss%/ how much loss or gain.

• LET CP OF 1 PEN=RE 1
  CP OF 20 PENS=RS 20.
  SP OF 2O PENS=CP OF 13 ARTICLES.
  LET CP OF 1 ARTICLE RE 1.
  CP OF 13 ARTICLES RS 13 ie EQUAL TO SP OF 20 PENS.
  SO LOSS=(20-13)= RS 7.
  LOSS%=7/20*100
  
• 8 years agoHelpfull: Yes(18) No(9)
• Ans=35% loss
  let CP of 13 article be x
  then,SP of 20 article will be Rs x
  so,SP of 1 article will be rs X/20
  and SP of 13 ariticle will be 13x/20
  loss= Cp-SP = x-(13x/20) =7x/20
  loss%= (loss/CP)*100 = 35%
• 7 years agoHelpfull: Yes(7) No(1)
• first of all i want you to tell the formulas of profit or loss. by knowing this formula you can do any kind of profit or loss sums
  
  c.p= cost of an article
  s.p = which an article is sold
  profit= if s.p > c.p then the seller is said to have profit (or) gain
  loss= if s.p < c.p the the seller is said to have loss
  profit (or) gain = (s.p) - (c.p)
  loss= (c.p)-(s.p)
  Gain% (or) profit%=(gain*100/c.p)
  loss%= (loss *100/c.p)
  so,
  given,
  cost of 13 articles= cost of pens
  let cost of 1 pen=1
  c.p=20; cost of 13 articles is 20
  s.p=13; 13 are sold out by seller
  loss=(s.p)-(s.P)
  = 20-13
  = 7
  loss%= (loss*100/c.p)
  = (7*100/20)
  = 35%
• 7 years agoHelpfull: Yes(7) No(0)
• CP of 13 article(n) = SP of 20 pen (m)
  
  formula = n-m/m *100
  13 - 20/20 * 100
  -7/20 * 100 = -35% (loss of 35%)
• 7 years agoHelpfull: Yes(4) No(0)
• 35%loss
  cp of 13 =sp of 20
  sp/cp=13/20
  13-20/20*100=35%
• 7 years agoHelpfull: Yes(2) No(0)
• Shortest possible solution:-
  Here S.P=0.6 (C.P)
  SP=(1-0.35)CP
  From above eq it is quiet clear that there is loss of 35%
• 6 years agoHelpfull: Yes(1) No(0)
• (3*18)÷18 = 16 23
• 8 years agoHelpfull: Yes(0) No(9)
• let the cp of 13 articles =x
  sp of 20 articles =x here i am selling more articles at the cp of 13 artcles therefore there is a loss of 7articles and that can be found by=7/20*100=35%
• 7 years agoHelpfull: Yes(0) No(1)
• (c.p~s.p/s.p)*100
  35%
• 7 years agoHelpfull: Yes(0) No(1)