A professor keeps data on students tabulates by performence and sex .unfortunately some data is lost





Average Good Excellant Total

Males ---- ------ 10 -----

Females ----- ------ ---- 32

Total ----- 30 ----- ----



Half the student are excellent or good

40% of the students were females

One third of male students were average Find lost valuese

• Given , number of Female students : 32
  40% of the students were female
  So, 40x/100 = 32
  so, x=80 ... the number of students.
  Thus , males = 80-32=48
  As given that one third males were average .. this leads to below fact:
  1/3 * 48 = 16 males were average.
  Thus remaining 22 males are good.
  
  Also given half the students are excellent or good as well as total 30 are good and 10 males are excellent. so number of excellent females = 0. Number of good females = 30 - 22 =8.
  Number of average females = 32 - 8 - 0 = 24.
  Total average students = 40
  
  
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• Avg Good Excellent Total
  Male 16 22 10 48
  Female 24 08 00 32
  Total 40 30 10 80
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