A railway track runs parallel to a road until a bend brings the road to a level crossing. A cyclist rides to work along the road every day at a constant speed of 12 miles per hour. He normally meets a train that travels in the same direction at the crossing. One day he was late by 25 minutes and met the train 6 miles before the level crossing. Can you figure out the speed of the train?

1) 72
2) 60
3) 48
4) 36

• assume the train and cyclist meet at 8;00am..
  so 6mile before the crossing it should at 7;30am.
  on 1 day the man is late bye 25min.
  so it should be at crossing at 8;25am.
  6mile before the crossing at 7;55am
  so train has to cover 6mile in 5min..so its speed should be 72mph..
  6/(5/60)=72
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• 123456
  no answer i need answer
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