can you find four numbers such that the sum of every two and the sum of all four may be perfect squares?

• The numbers are 10430, 3970, 2114 and 386.
  The solution depends on the fact that every prime number in the form 4m+1 is the sum of two squares.
  For example
  (82)^2+(57)^2 + (21)^2+(4)^2
  
  =9973 +457
  
  =10430
  
  Try to find other numbers in this way, friends.
• 2 years agoHelpfull: Yes(0) No(0)