foreign language broadcaste records last 75min on each of two sides if it take 3hrs to translate one hour of broadcast how long will it take to translate 20 full records?

2)a car departs at 11:10am.it travels at 110km/hr until 2:30 then it reduces its speed by 5%for the remainder of trip.it reaches destination at 7:30.How much kilometer did he travel?

3)a car of cost89000, it depreciates 6000in first year , increment 3%, after 4 years=?

• time taken to complete one record is 75*2=150,150/60=2.5hrs
  so 2.5*20=50 full records
  3 hrs to take onr hr broadcast ,so 50*3=150
  ans:150
• 8 years agoHelpfull: Yes(9) No(0)
• 2) 11:10 to 2:30= 50 min+60min+60min+30min=>(550/6 +110+110+55)km=366.66km
  2:30 to 7:30
  speed=110 minus 5% of 110=104.5km/hr
  dist traveled = 104.5*5=522.5kms
  total dist=522.5+366.66=889.16
• 8 years agoHelpfull: Yes(9) No(1)
• time taken to complete one full record is 75*2=150 minutes
  total records is 20. so, 150*20=3000 minutes recording
  given 3hrs to translate 60 minutes recording
  so, f0r 3000 minutes of recording takes
  (180/60)*3000=9000 minutes
  
• 8 years agoHelpfull: Yes(7) No(2)
• Records last 75 min on each of 2 sides,
  -----> record last 75*2 = 150 min = 2 hours 30 minutes=2.5 hours
  
  20 full records--> 20*2.5 = 50 hour broadcast
  
  Given, 3 hours to translate 1 hour of broadcast
  Let x be the time required to translate 50 hour broadcast(20 full records)
  
  x = 50*3
  =150 hours
  
• 8 years agoHelpfull: Yes(2) No(0)
• Anyone please share the answer of 3rd question
• 7 years agoHelpfull: Yes(1) No(0)
• 3) In first year it depricates so 89000-6000=83000
  we have calculated for first year then for next 3 years there is increment of 3% so,3*3=9%of original cost which is 0.09*89000=8010
  since,there is increment so we will add values of all the years 83000+8010=91010.
• 7 years agoHelpfull: Yes(1) No(0)
• 3.) 1st yr depreiciated amount 6000 ,therefore new amount is 89000-6000=83000,it said to find amount after 4 yrs with depreciation rate 3%,as for 1st yr we got the new amount,we have to find the amount after left 3 yrs. Using the formula
  A=P(1-r/100)^3.= 83000(1-3/100)^3=75751.859=75752
• 7 years agoHelpfull: Yes(0) No(3)
• 9.) Server costs A 2/10 more than 6/10 the price of server B. if server A and B both cost $25000 together, what is price of server A?
  please solve this one
• 7 years agoHelpfull: Yes(0) No(0)