what would be the value of (log a)^2 -(log b)^2

a) log(a+b)log(ab)
b) 3
c) lo(ab)log(a/b)
d) None

• Question is in the form of a^2 - b^2 so the formulae is
  (a+b)(a-b)=a^2 - b^2 where a=loga,b=logb
  substitue in the formulae we get
  (loga+logb)(loga-logb)
  (log(ab))(log(a/b))
• 7 years agoHelpfull: Yes(26) No(0)
• (a^2)-(b^2)=(a+b)(a-b)
  & (Log a)^2 is not equal to Log a^2
  
  so....(log a)^2 -(log b)^2 = ((log a) + (log b) )((log a) -(log b) )
  -->log(ab) log(a/b)
• 7 years agoHelpfull: Yes(3) No(0)
• d none
  (log a)^2-(log b)^2=(log a +log b) (log a - log b)
  =(log ab) log(a/b)
• 7 years agoHelpfull: Yes(2) No(1)
• c.log(ab)log(a/b)
• 6 years agoHelpfull: Yes(2) No(1)
• jayanth ur ans is right but if we go through log mechanism an will be 2loga-2logbso 2loga/2logb=loga/logb
• 7 years agoHelpfull: Yes(1) No(4)
• this in form that a^2-b^2
  so (a+b)(a-b)=a^2-b^2
  so log(ab)log(a/b)
• 7 years agoHelpfull: Yes(1) No(0)
• (log a)^2 - (log b)^2
  ={(log a)+(log b)} * {(log a) - (log b)} Putting a^2 - b ^2 = (a+b)(a-b)
  =log(ab)*log(a/b)
  
  Ans : C
• 7 years agoHelpfull: Yes(1) No(0)
• it is in the form of a2-b2=(a+b) (a-b)
  a=loga, b=logb then substitute in the question we get;
  (loga+logb)(loga-logb)=log(ab)log(a/b)
• 6 years agoHelpfull: Yes(1) No(1)
• (log a+log b)(log a-log b)
  log ab.log a/b
• 7 years agoHelpfull: Yes(0) No(0)
• = 2( log a - log b)
  = 2 (log (a/b))
• 7 years agoHelpfull: Yes(0) No(4)
• (log a)^2-(log b)^2
  (a^2-b^2)=(a+b)(a-b)
  (log a+log b)(log a-log b)
  log(ab)log(a/b)
  Ans (C)
• 6 years agoHelpfull: Yes(0) No(0)
• hello, are questions repeated in capgemini written test and can you share the questions pls, i have to crack the first round.
  sunilmalviya23061996@gmail.com
• 5 years agoHelpfull: Yes(0) No(0)
• Please share the questions are repeated in capgemini written test bcz I hv to crack the first round preethinaik531@gmail.com
• 4 years agoHelpfull: Yes(0) No(0)