There is a square with side ‘a’ and one octagon is inscribed in it. What will be perimeter of octagon.

• let side of the octagon = f
  as octagon is inscribed in the square
  therefore
  each side of square share 1 side of octagon and the remaining side left = a-f
  since the corner of two side of square makes a right angled Isosceles triangle
  therefore
  [(a-f)/2]^2+[(a-f)/2]^2=f
  f=(a-f)/root2
  f=a/(root2+1)
  
  perimeter of octagon is 8a/(root2+1)
• 7 years agoHelpfull: Yes(14) No(0)
• Well if it's a regular octagon then it actually trisects each side of the square in which 1/3 of the lenght of the side of the square is the length of one side of the octagon. If any one has a doubt he can draw the figure and see it
  Going this way lenght of a side of a octagon is a/3 and thus perimeter would be 8a/3.
• 7 years agoHelpfull: Yes(6) No(6)
• no. the ans will be 4a/3(1+root2)
• 7 years agoHelpfull: Yes(4) No(2)
• 8a/(sqrt(2)+1)
• 7 years agoHelpfull: Yes(2) No(0)
• The octagone trisects the square ,so side of octagone will be a/3.Now like perimeter of square is 4a ,the perimeter of otagone is 8a=8Xa/3=8a/3
• 7 years agoHelpfull: Yes(1) No(7)
• (root2-1)8a=3.31a
• 7 years agoHelpfull: Yes(1) No(3)
• Ans : 8a/3
• 7 years agoHelpfull: Yes(0) No(4)
• perimter = 4 x a
• 7 years agoHelpfull: Yes(0) No(6)
• Ans : 8a/3
• 7 years agoHelpfull: Yes(0) No(4)
• 4*(a/3)+4*root[(a/3)^2+(a/3)^2] = a/3(4+0.717) =4.71(a/3) ans
• 7 years agoHelpfull: Yes(0) No(1)
• you cannot fix an octagon as you are imagining mr. Rohit
• 7 years agoHelpfull: Yes(0) No(0)
• 8a/(1+2(root 2))
• 7 years agoHelpfull: Yes(0) No(0)