The average age of three members in a team A B C ,3 years ago was 33 years and that of B and C, 7 years ago was 35 years find present age of A

• Ans : 18 yrs
  
• 8 years agoHelpfull: Yes(0) No(0)
• Ans : 24 yrs
• 8 years agoHelpfull: Yes(0) No(0)
• age of mem 3Years ago = 33*3 =99
  
  present age of those 3 mem = 99+(3*3) = 108
  
  age of B and C 7 years ago = 35*2= 70
  
  present age of B and C = 70+(2*7) = 84
  
  A+B+C+(B+C) = 108-84 =24y
• 8 years agoHelpfull: Yes(0) No(0)
• Sum of age of members 3 Years ago = 33*3 =99
  
  So present age of those 3 members = 99+(3*3) = 108
  
  Sum of age of B and C 7 years ago = 35*2= 70
  
  So present age of B and C = 70+(2*7) = 84
  
  A+B+C-(B+C) = 108-84 =24 years
• 7 years agoHelpfull: Yes(0) No(0)