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In a compiler there is 36 bit for a word and to store a character 8bits are needed. IN this to store a character two words are appended .Then for storing a K characters string, How many
words are needed.
[a] 2k/9
[b] (2k+8/9
[c] (k+8/9
[d] 2*(k+8/9 [e] none

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In compiler,

word=36 bit
char= 8bit
tp store k char= 8k/36=2k/9

so ans is A. 2k/9
7 years agoHelpfull: Yes(7) No(1)

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In a processor these are 120 instructions . Bits needed to implement this instructions
[a] 6
[b] 7
[c] 10
[d] none Virtual memory size depends on
[a] address lines
[b] data bus
[c] disc space
[d] a & c [e] none