a rectangular block has the dimensions 5*6*7 cm it is dropped into a cylindrical vessel of radius 6cm and height 10 cm.if the level of the fluid in the cylinder rises by 4 cm,what portion of the block is immersed in the fluid.

A)22/7*15/18
B)22/7*24/35
C)22/7*22/34
D)22/7*12/15

• Since level of water increased in cylinder by height 4.
  This is because of the rectangular block .
  
  Therefore , area of rectangular block immersed in water is = 22/7 * (6)^2 * 4
  
  Thats why portion of block immersed in water is= (22/7 * 36* 4) / total vol of rectangle
  = (22/7 *36*4)/ (7*5*6)
  = 22/7 *24/35.
• 8 years agoHelpfull: Yes(9) No(7)
• want answer
  
• 8 years agoHelpfull: Yes(4) No(7)
• Ans : B)22/7*24/25
  
  volume increase in cylinder=(volume of block *portion of it which is immersed)
  22/7*62*4 = 5*6*7( p)
  p = 22/7*36*4
  5*6*7
  
  p = 22/7*24/35
• 7 years agoHelpfull: Yes(2) No(1)