A HEXAGON IS FORMED ABCDEF WHICH PERIMETER 36cm. A POLYGON IS FORMED BY JOINING THE POINTS AE &BD . FIND THE AREA OF THE POLYGON ABDE?

• A regular hexagon consist of 6 equilateral triangle. Each of side 6 cm.
  So the area of 1 equilateral triangle is = ¼(√3 a2) = 9√3 cm2
  The figure formed by joining polygon ABDE consist of 2 equilateral triangle and 4 half equilateral triangle
  Which employs area of 4 equilateral triangle.
  So, The area of polygon ABDE = 4*(area of equilateral traingle)
  = 4* 9√3 = 36√3 cm2 Answer
  
• 8 years agoHelpfull: Yes(14) No(0)
• AB=36/6 =6
  AE=BD= 6√3
  
  area of rectangle ABDE = 6*6√3 = 36√3
  
• 8 years agoHelpfull: Yes(5) No(2)
• ABDE is a rectangle. So, Area = AB x BD. From hexagon AB=BC=CD=DE=EF=FA=36/6=6cm. BD^2=BE^2-DE^2. Here BE = 12cm and DE = 6cm So BD = 6√3cm now area of ABDE = 6 x 6√3 = 36√3 sq cm.
• 8 years agoHelpfull: Yes(4) No(2)
• Area of rectangle=4*[root(3)/4]*sqaure(6)
• 8 years agoHelpfull: Yes(2) No(0)
• its 8.485
  reason is when hexagon is make a polygon then two sides are equal in a trinangle the third side is like a hypotenuse then we use the formula p^2 + b^2=h^2
• 8 years agoHelpfull: Yes(0) No(3)
• length of AE=BD= 2*6=12. length of AB=ED=6. Area of ABDE=12*6= 72
• 8 years agoHelpfull: Yes(0) No(7)
• all sides are equal. so it is square. area of square is s*s=6*6=36.
• 8 years agoHelpfull: Yes(0) No(5)
• plzzzzzz friends can u tell me how can AE=12
• 8 years agoHelpfull: Yes(0) No(2)
• 36*sqrt(3)
• 8 years agoHelpfull: Yes(0) No(0)
• ABCDEF is a regular polygon,hence it consist of 6 equi. triangles.Let O be the center of the hexagon and also the polygon ABDE. AB=ED=OE=OC=6(perimeter of hexagon is given),since OED=OAB are equi. triangle.
  EB is a diagonal of polygon ABDE and it comes out to be 12.By pyth. theorem AE=6root3.
  Area=AE*AB=36root3
• 8 years agoHelpfull: Yes(0) No(0)