Elitmus
Exam
Logical Reasoning
Cryptography
Ask in elimus 25Dec 2016.
A V E
E H L
-------------
Z H E S
S Z Z P__
D W Z S__
---------------
E V A H E S
Read Solution (Total 6)
-
- AVE*L=ZHES.....(1)
AVE*H=SZZP......(2)
AVE*E=DWZS.....(3)
there is one clue that E+P=E [due to this condition we know that value of P will be 0...
now take equation 2..and put A=9,V=3,E=2,H=5
932*5=4660
now Z=6,S=4,P=0
again take eq1- and put L=7
932*7=6524, (sutisfied)
check the eq3-
932*2=1864(sutisfied)
finally all values are
A=9,V=3,E=2,S=4,H=5,L=7,Z=6,D=1,W=8... - 8 years agoHelpfull: Yes(16) No(13)
- here u can start a q. with one clue , p=0
P = 0
V = 3
S = 4
H = 5
L = 7
Z = 6
D = 1
W = 8
A = 9
E = 2 - 8 years agoHelpfull: Yes(2) No(8)
- as e+p=e
therefore p=0
substitute 0 instead of p
e*5=0 this implies e should be even no.
from the hundreadth column you get 5+z+s=5
this lead you with 5+z+S=15
therefore z+s=10
6+4
8+2
7+3
9+1
lets try with (6,4)substitute 6 instead of z and 4 instead of s
ave ave ave
*e *5 *l
------- -------- -----------
dw64 4660 65e4
e*e=4 (e can be 2,8)
let e=2 with v=3 ad a=9 satisfy alll three
this yield dw as 18 - 7 years agoHelpfull: Yes(1) No(1)
- 932
257
-----
6524
4660
1864
-------
239524 - 8 years agoHelpfull: Yes(0) No(3)
- How to solve : https://www.youtube.com/watch?v=dJ0asyKvl1I&t=10s
- 8 years agoHelpfull: Yes(0) No(3)
- 9 3 2
2 5 7
---------
6 5 2 4
4 6 6 0
1 8 6 4 - 7 years agoHelpfull: Yes(0) No(2)
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