CAT Exam Numerical Ability Ratio and Proportion

Ajay went to the market to buy a total of 90 apples , oranges and bananas . HE bought an equal number of apples and bananas .

The ratio of the number of apples and oranges he bought is 5:2

If the price of each was equal to that of each apple ,he could hav skipped the purchase of bananas and instead purchased the same number of apples and oranges as he actually bought for the same total amount .

If the prices r all integers , find the minimum possible total expenditure he could hav incurred in RS.

Read Solution (Total 1)

A = apples , O = Oranges , B = Bananas
A+O+B =90 ...
O=B
A/O = 5/2
So, 5x +2x+2x =90
x=10.
So, 50 Apples and 20 oranges/bananas
50A +20O +20B = Total
50A +20A (cost of apples n oranges are same) +20B = Total
Instd of 20B .. 50A + 20A(oranges)

So, 2(50A +20A ) = Total
140A = Total
So, multiple of 140 in the options ie 140 is the answer.
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