(10^10+10^10^2+10^10^3+10^10^4+10^10^5+10^10^6+10^10^7+10^10^8+10^10^9+10^10^10)/7 what will be reminder??

1) 1
2) 4
3) 5
4) none of this

• take 1st term 10^10/7 will give remainder as 10/7 = 3
  therefore, 3^10/7 equivalent to (3^3)^3.3/7
  => (3^3)^3.3/7 = (27)^3.3/7
  27 divided by 7 give remainder as -1
  => (-1)^3.3/7 = (-1).3/7
  now,-1 can be replaced by 6 as -1+7=6
  => 6.3/7 = 18/7
  => 18/7 = 4
  similarly every term will give remainder 4 when divided by 7
  therefore, 4+4+4+4+4+4+4+4+4+4/7 = 40/7
  and 40/7 gives remainder as 5
  
  Ans is 5
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