2 computer each produces 4800 utility bills in a day. First computer bills at a rate of 9600 per hour while other at the rate of 7800 per hour. When first computer finished its run, how many bills did the other computer still have to print?
A. 200
B. 1000
C. 900
D. 850

• the question is wrong..its 48000 not 4800
  
  48000=9600*Hour
  Hour =5
  
  7800*5=39000
  
  48000-39000=9000
  
  ans 9000
• 7 years agoHelpfull: Yes(14) No(11)
• first computer take 30 minit to print 4800 bills than stop working thus second computer will print for 30 minit. hence second computer print per minit= 7800/60 = 130(in one minit)
  hence in 30 minit 130*30= 3900
  remain to print 4800-3900=900
• 7 years agoHelpfull: Yes(14) No(1)
• the correct answer is 9000
  
  workings...
  
  48000 / 9600 = 5
  5 * 7800 = 39000
  therefore 48000 - 39000 = 9000
• 7 years agoHelpfull: Yes(5) No(1)
• 4800=9600*Hour
  Hour =.5
  
  7800*.5=3900
  
  4800-3900=900
  ans 900
• 7 years agoHelpfull: Yes(4) No(0)
• 1st com per hr=9600 then completes 4800 in 1/2 hr.
  other com per hr=7800 then for 1/2 hr only 7800/2=3900
  remaining=4800-3900=900
  so ans:900
• 7 years agoHelpfull: Yes(1) No(0)
• 48000/6=5 hrs
  so we have 5 hrs
  1st Com. print the bill in that time is =5*9600=48000
  2nd=5*7800=39000
  so 48000-39000=9000ans
• 7 years agoHelpfull: Yes(0) No(0)
• x=48000(total bill in a day)
  x1=9600
  x2=7800
  x/x1=48000/9600=5
  5 total time by x1
  5*x2=5*7800=39000
  x-39000=48000-39000=9000
• 7 years agoHelpfull: Yes(0) No(0)
• Plz can anyone send me the previous papers of Capgemini
  My email id sailajanarayan38@gmail.com
• 5 years agoHelpfull: Yes(0) No(0)