IBM
Company
Numerical Ability
Sequence and Series
1) 4,6,9,13,18,24,31,?
2)2/3,5/3,3 1/6,3 1/6,7 8/5, 3 2/3,14 1/6,?
3)2.2,5.5,8,36,40.5,203.25,?
4)1,-1,2,-6,2,-2,4,-12,3,?
5)340,680,1428,3141.6,?
6)1/3,1/2,1/4,2 1/3,3 1/2,4 1/4,4 1/3,6 1/2,?
7)37,73,9,49,58,85,25,64,29,92
8)36,42,16,20,36,42,4,2,?
9)4,11,66,74,370,379,?
10)0,1,2,0.5,2,3,5,1,2,0,2,1,4,?
Read Solution (Total 19)
-
- 1) 4 6 9 13 18 24 31 ....
Ans... 39
Difference btw terms= 2 3 4 5 6 7 & last one is 8. - 7 years agoHelpfull: Yes(9) No(0)
- 9)4,11,66,74,370,379,?
4+7=11,11*6=66,66+8=74,74*5=370,...379*4=1516,1516+11=1527 - 7 years agoHelpfull: Yes(8) No(2)
- 5) ans is 7225.68
340,680,1428,3141.6_____
340*2=680*2.1=1428*2.2=3141.6*2.3=7225.68 - 7 years agoHelpfull: Yes(7) No(0)
- 3..
2.2,5.5,8,36,40.5,263.25,340,748,1714,?
(2.2,5.5),(8,36),(40.5,263.25),(340,748),(1714,x)
5.5/2.2 = 5/2
36 / 8 = 9/2
263.25/40.5 = 13/2
748 / 340 = 17/2
SO , X / 1714 = 21/2
THEN : X = 1714*21/2 = 17997
Ans :: 17997 - 7 years agoHelpfull: Yes(6) No(8)
- 7) ans
( 37, 73, 9=3^2( i.e square of first digit of 37 ) , 49=7^2( i.e square of second digit of 37))
(58,85, 25=5^2 (i.e square of first digit of 25), 64=8^2(i.e square of second digit of 58))
similarly (29,92,4,81) - 7 years agoHelpfull: Yes(5) No(0)
- 4) Ans= -3
- 7 years agoHelpfull: Yes(5) No(0)
- 8) 36,42,16,20,36,42,4,2,?
(36,42) repeating after two numbers .. so next terms will be 36,42 - 7 years agoHelpfull: Yes(5) No(2)
- 2) ans.... 18 1/6
(2/3),(5/3),(19/6),(31/6),(23/3),(32/3),(85/6),?
[(2/3),(5/3)],[(19/6),(31/6)],[(23/3),(32/3)],[(85/6),x]
5/3 -2/3 =1
31/6 -19/6=2
32/3 -23/3=3
(x- 85/6)=4 =>x=85/6+ 24/6 = 18 1/6 - 7 years agoHelpfull: Yes(3) No(2)
- 1) 31+8=39.
- 7 years agoHelpfull: Yes(2) No(0)
- 10) (0,1,2,0.5) -> (0+1)/2=0.5
(2,3,5,1) -> (2+3)/5 = 1
(4,2,3,?) ->(4+2)/3 = 2
Soln : 2 - 6 years agoHelpfull: Yes(2) No(1)
- 6)ans --4 17/4.
1/3+2=2 1/3(4th), 1/2+3=3 1/2(5th), 1/4+4=4 1/4(6th)
now do the similar steps again with the next 3, at 3rd position U will get Ur ans.
(2 1/3 or 7/3)+2=4 1/3, (3 1/2 or 7/2)+3=6 1/2, (4 1/4 or 17/4)+4=( 4 17/4 ).... - 7 years agoHelpfull: Yes(1) No(5)
- 2) ( 2/3) , (5/3) , (19/6) , (31/6) , (23/3) , (32/3) , (85/6) , ?
ans=109/6
2/3+1=5/3
19/6+2=31/6
23/3+3=32/3
85/6+4=109/6(ans) - 6 years agoHelpfull: Yes(1) No(1)
- Ans:1) 39(subtract the every 2nd term with the 1st term)
- 6 years agoHelpfull: Yes(1) No(0)
- 6) 1/3, 1/2, 1/4, 2 1/3, 3 1/2, 4 1/4, 4 1/3, 6 1/2, ?
==> 3 numbers as a group --
the first number of the group: 1/3, 2 1/3, 4 1/3
the 2nd number of the group: 1/2, 3 1/2
the 3rd number of the group: 1/4, 4 1/4, x
x = 8 1/4 - 6 years agoHelpfull: Yes(1) No(0)
- 2)2/3,5/3,3 1/6,3 1/6,7 8/5, 3 2/3,14 1/6,?
is this question right ???
if yes then plz solve this... - 7 years agoHelpfull: Yes(0) No(1)
- 7)
take pair of (37,73), (58,85) and (29,92)
now 9 and 49 are square of 3 and 7 resp.
25 and 64 are square of 5 and 8 resp.
so the next no will be square of 2 i.e 4 - 7 years agoHelpfull: Yes(0) No(1)
- Q1. 4+2=6
6+3=9
9+4=13
13+5=18
18+6=24
24+7=31
31+8=39
answer is 39 - 7 years agoHelpfull: Yes(0) No(0)
- 4. ans should -3
each term in the series multiplied by -1 and -3 alternately
1*-1=-1
2*-3=-6
2*-1=-2
4*-3=-12
3*-1=-3
ans is -3 - 7 years agoHelpfull: Yes(0) No(0)
- 6) ans= 8 1/4
- 6 years agoHelpfull: Yes(0) No(0)
IBM Other Question
-23,-16,18,14,-52,-45,37,33,-65,
IBM SERIES QUESTIONS
1)7,-35,-24,-3,15,16,4
2)4,6,2,12,18,14
3)5,10,9,3,6,5,4,8,7,7
4)4,2,5,9,5,11,31,7,16,7,9
5)33,8,41,46,21,67,72,47,119
6)100,98,95,90,83
7)1/7,3/4,4/9,5/6,7/11,7/8,
8)7,0,1,8,5,12,9,26,3,23,2,28
9)1,3,3,2,8,10,3,4,12,4,8,12
10)1,3,1,2.5,5,1,4,5,4,8,7
11)1/2,1/2,1/4,1/6,1/8,1/18,1/16.
12)2,3,10,15,26
13)12,22,35,68,15,28,31
14)0,1,2,.5,2,3,5,1,2,0,2,1,4,2,3
15)36,42,16,20,36,42,4
16)0,1,0,2,2,2,3,4,5,6,6
17)35,7,48,24,75,15,16,8,80
18)2,1/3,2/3,6,7,1/2,31/2,14,20,1/5,4