IBM
Company
Numerical Ability
Arithmetic
1.)In a normal 6-day work week, each of 12 employees produces 260 items per day. Last week, ¼ of the employees were
absent from work for 3/6 of the days in the week. How many total items were produced last week?
2.) A project requires 40 hours from each of three employees to complete. Each employee is paid
$25 per hour. If the company hires a contractor for $ 10 per hour, and the four divide the total amount of work equally,
how much would is cost to complete the audit?
3.) A sales person sold an average of 7 computers per week for the first 44 weeks of this year. Last year this salesperson sold a tota
of 24440 computers.To equal last year’s performance, how many computers must the salesperson sell per week in the remaining weeks of the year?
4.) A car departs at 9:10 am. It travels at 152 kilometers per hour until 5:40 pm, then increases its speed by 5% for the remaining
of the trip. It reaches its final destination at 9:10 pm. How many kilometers did the car travel?
5.)) In a 200 runner A can beat runner B by 3.5 meters. If they run a t the same pace in
2400 meters race, runner A will beat runner B by
meter race,
6.) A person is responsible for loading reviews of computer games and desktop computers onto a
website. It takes 120 minutes to load a half-page review. How long will it take to load half-page reviews
for each of 4 desktop computers, plus full-page reviews for each of 2 computer games?
7.)) A new car is driven 878 miles in year 1. It is driven 1150miles in year 2. In each of year3, 4, and 5 car is driven 4% more miles than in the
previous year. How many total miles has the car been driven at end of year 5?
8.) Company A hired a contract programmer at $25 per hour to complete 3 projects, each lasting
200 hrs. The programmer also incurred travel expenses averaging $22 per project. If the company b had
the same work done under a fixed price contract for $14175 that included all labor and travel expenses, which company would pay
how much more than the other?
9.) Server costs A 2/10 more than 6/10 the price of server B. if server A and B both cost $25000 together, what is price of server A?
10) A printer prints 85 pages per minute. If the printer printed for 4 hours, except for 12 minutes when
there was a paper jam, how many pages did it print?
11.) Two printers are printing pages. The first printer prints 21 pages per minute. The second printer prints 40 pages per minute.
If the second printer printed for 4 ½ hours, how many minutes would it take for the first printer to print the same number
of pages as the second printer?
Read Solution (Total 33)
-
- 2.
total hrs= 120
Divide by 4= each get 30 hr
so, each one of three worker got 750 (30*25)each and contractor got 300( 30*10).
Total cost= 750*3+300=2550.
go ahed... - 7 years agoHelpfull: Yes(18) No(0)
- 3.
7 computers for 1 week
for 44 weeks 7*44=308 computers
a year has 52 weeks..
so 52-44 =8 ( weeks left)
given last year he sold 24,440 computers for 52 weeks..
so for remaining 8 weeks he must sell ( 24,440-308 = 24,132)
it means 8 weeks ...... 24,132 computers
soo for 1 week...........24,132 / 8 =3,016 computers - 7 years agoHelpfull: Yes(14) No(1)
- 8.----------------------------------------891
- 7 years agoHelpfull: Yes(13) No(1)
- 10.)4hrs=4*60=240min
except 12 mins, so 240-12=228mins
85*228=19380 pages - 7 years agoHelpfull: Yes(12) No(0)
- 11.-------------------------------514.28 min
- 7 years agoHelpfull: Yes(11) No(0)
- 1.
1 day=260*12
6 day= 260*12*6==18720
work of absent worker in 3 days of 3 worker=260*3*3=2340
so work done= 18720-2340=16380 - 7 years agoHelpfull: Yes(10) No(18)
- 7.
878 miles-year 1
1150 miles- year 2
1196 mile-year 3
1243.84 miles- year 4
1293.5 miles-year 5 - 7 years agoHelpfull: Yes(10) No(2)
- 4. ans-------------------1850.6
- 7 years agoHelpfull: Yes(9) No(13)
- 5.-----------------------42 metre
- 7 years agoHelpfull: Yes(9) No(1)
- 1)
total item produce by 12 employee in 5 days.
= 12*6*260
=18720 items
item produce by those absent empoyee
=3*3*260
=2340 items
so originally total item produce
=18720-2340
= 16380 items Ans. - 7 years agoHelpfull: Yes(9) No(2)
- 9. can anyone explain me the 9th bit?
- 7 years agoHelpfull: Yes(8) No(0)
- 1. Each of 12 employees produces 260 items per day, Last week 1/4 employees were absent 12/4=3 employees were absent 3days work of remaining 8 employees
8*3*260=6240
3 days work of all 12 employees
12*3*260=9360
so,Items were produced last week=6240+9360
=15600 items - 7 years agoHelpfull: Yes(5) No(16)
- 10-19380
1min------85pg
60min------85*60=5100
4hr-------5100*4=20400
12min------85*12=1020
20400-1020=19380ans - 7 years agoHelpfull: Yes(4) No(0)
- 6) ------------------------------------960
- 7 years agoHelpfull: Yes(4) No(0)
- 7) 1292 km after 5 years. because for every previous year, we need to add 4%.
- 7 years agoHelpfull: Yes(3) No(1)
- 1)
per six days 12 employees produces the 6*12*260=18720
Last week, ¼ of the employees were
absent from work for 3/6 of the days in the week means 12/4=3 employees were absent .
means 8 employees were doing production for 3 days: 3*8*260=6240
in remaining days work done is 3*12*260=9360
so work done in last week is= 9360+6240=15600
2) - 7 years agoHelpfull: Yes(3) No(0)
- 8.) company A pays 15066
company B pays 14175
diff=15066-14175= $891
so Ans compA pays 891$ more than comp B - 7 years agoHelpfull: Yes(2) No(0)
- 9) A=2/10+(6/10)B
A+B=2500
2/10+(6/10) B+B=2500 (OR) A=2/10+6/10(2500-A)
Solve above equation
Then A=937.625 - 7 years agoHelpfull: Yes(2) No(4)
- 11) let x minutes to print the pages for first printer
given first printer prints 21 pages per minutes so 21*x
given second printer prints 40 pages per minutes so 40*270=10800 ( 4 1/2 hr= 270 minutes)
so 10800=21*x
then x= 514.28 minutes for first printer - 7 years agoHelpfull: Yes(2) No(0)
- 6)
half page review = 120 mins = 2 hrs.
to load 4 computers with half page review = 4*2 = 8 hrs
to load 2 computers with full page review = 2 * (2+2) = 8 hrs
total = 16 hours. - 7 years agoHelpfull: Yes(2) No(0)
- 4)
difference between 9.10 am to 5.40 pm=8hr 30 min
each hour travel =152km
8.5*152=1292km
the speed increases by 5%
152*5/100=7.6
152+7.6=159.6km/hr
diff b/w 5.40 pm to 9.10 pm=3hr 30 min
3.5*159.6=558.6
now,total distance travelled =1292+558.6
=1850.6km - 7 years agoHelpfull: Yes(2) No(3)
- 9....---------------960 min
- 7 years agoHelpfull: Yes(1) No(8)
- 7.--------------------------------5737.35 miles
Happy Saraswati puja to all 2k17 - 7 years agoHelpfull: Yes(1) No(13)
- Can anyone explain 6th bit
- 7 years agoHelpfull: Yes(1) No(2)
- can anyone solve the question no 3?
- 7 years agoHelpfull: Yes(1) No(0)
- 1) each employ can produce 260 items per day
1/4 of 12 emploies=3 and 3/6 of 6days =3
therefore 3 emploies are absent for 3 days
=260*3*3=2340 and 260*9*6=14040
total items =16380 - 7 years agoHelpfull: Yes(1) No(0)
- B= x
A= 2/10(6x/10)
A+B=25000
By solving above equations we get
A= 2499(apx)
B=20833 - 7 years agoHelpfull: Yes(0) No(1)
- radhakantha behera am unable to understand the solution no.2..plzz explain me properly
- 7 years agoHelpfull: Yes(0) No(0)
- ans.6
120*4=480
480/60=8hrs - 7 years agoHelpfull: Yes(0) No(1)
- 10. 85 .....min
so 10,660 - 7 years agoHelpfull: Yes(0) No(0)
- can u explain me 9th question related to server
- 7 years agoHelpfull: Yes(0) No(1)
- Can you please explain 9. Question
- 7 years agoHelpfull: Yes(0) No(0)
- 4. Time interval 9.10 am to 5.40 pm = 8.5 hours
5.40 pm to 9.10 pm = 3.5 hours
Find the distance traveled in the first part of the journey:
Speed = 152 km/h, Time = 8.5 hours
Distance = 152 x 8.5 = 1292 km
Find the speed for the second part of the journey:
Speed increase = 5% of 152 km/h
Speed increase = 0.05 x 152 = 7.6 km/h
Speed = 152 + 7.6 = 159.6 km/h
Find the distance traveled in the second part of the journey:
Speed = 159.6 km/h
Time = 3.5 hours
Distance = Speed x Time
Distance = 159.6 x 3.5 = 558.6 km
Find the total distance:
Total distance = 1292 + 558.6 = 1850.6 km
The total distance traveled is 1850.6 km - 4 years agoHelpfull: Yes(0) No(0)
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