if we permute 8 letters of the word computer in 8! ways,how many permuted words have 'p' and 'e' next to each other?

• As 'p' and 'e' are always next to each other, we can group them into one entity.
  So we have 7 entities which can be grouped in 7! ways. Again 'p' and 'e' can be arranged amongst themselves in 2! ways.
  Therefore by theorem of multiplication, total number of ways= 7! *2!
• 7 years agoHelpfull: Yes(3) No(0)
• 7!2!=7*6*5*4*3*2*1*2
• 6 years agoHelpfull: Yes(2) No(1)